Answer: A. An OPEN circle on the number 5 and an arrow shading to the RIGHT.
Answer:
- arc BF = 76°
- ∠M = 31°
- ∠BGE = 121°
- ∠MFB = 111°
Step-by-step explanation:
(a) ∠FBM is the complement of ∠FBC, so is ...
∠FBM = 90° -52° = 38°
The measure of arc BF is twice this angle, so is ...
arc BF = 2∠FBM = 2(38°)
arc BF = 76°
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(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...
∠M = (1/2)(138° -76°) = 62°/2
∠M = 31°
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(c) arc FC is the supplement to arc BF, so has measure ...
arc FC = 180° -arc BF = 180° -76° = 104°
∠BGE is half the sum of arcs BE and FC, so is ...
∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2
∠BGE = 121°
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(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...
∠MFB = 180° -∠M -∠FBM = 180° -31° -38°
∠MFB = 111°
Answer:
Z=16
Step-by-step explanation:
just add 12 to both sides so you are left with only Z on one side
Answer:
88 centimeters is the diameter of the cilinder
Step-by-step explanation:
The pressure on both ends of the lift must be the same. Assuming the piston is cilindrical, its area will be A=π*r² where r is half the diameter
Since pressure P=F/A And P1=P2
F1=2000kg.g
A1=π*r²
F2=25kg.g
A2=π*0.05²
2000/(π*r²)=25/(π*0.05²)
and we solve for A1
r²=2000*0.05²/25

r=
20*0.05/5=0.44m or 44cm
This is the radius, meaning that the diameter will be twice this number