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zalisa [80]
2 years ago
5

Rewrite the equation y - 3 = 23(x - 2) in standard form.

Mathematics
1 answer:
jeka57 [31]2 years ago
7 0

Answer:

I believe it would be y-3=23x-2

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What is the value of x?<br><br><br><br> Enter your answer in the box.<br> x =
Shkiper50 [21]
If there is no equation that means that x could equal anything.
4 0
3 years ago
A college student completed some courses worth 3 credits and some courses worth 4 credits. The student earned a total of 59 cred
DedPeter [7]

Answer:

They completed 13, 3 credit classes

Step-by-step explanation:

1. Make 2 formulas. In this case: x+y=18

and 3x+4y=59

2. Then multiply x+y=18 by 3 and subtract the two equations.

Find y which is 5 and input into the equations. Then find your answer.

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3 years ago
What number divided by 5 equals 7
Verizon [17]

35 . because 5 times 7 equal 35 so 35 divide by 7 equal 35
3 0
3 years ago
Marissa's Fashions purchases designer boots from a manufacturer for $50.88 per pair. Marissa then adds a certain amount to the p
KATRIN_1 [288]

Answer:

Markup of _66.67_ % or $ _33,92_ per pair of boots

Step-by-step explanation:

In order to find the markup per pair of boots, we need to find the sales price BEFORE tax.

That can be done simply with a cross-multiplication (106.25 represents total price with 6.25% tax, and 100 represent amount of sales before tax)

\frac{90.10}{106.25} = \frac{x}{100}

if we isolate x we have x = (90.10 * 100) / 106.25 = $84.80

We can then easily calculate the markup amount, since the boots were sold $84.80 and Marissa paid $50.88, that means her markup amount is $33.92.

Now, let's calculate the markup percentage by see how much $33.92 represents compared to the initial price of $50.88:

$33.92 / $50.88 = 66.67%

6 0
3 years ago
Four teams A,B,C, and D compete in a tournament, and exactly one of them will win the tournament. Teams A and B have the same ch
beks73 [17]

Answer:

A= 0,2

B= 0,2

C= 0,4

D=0,2

Step-by-step explanation:

We know that only one team can win, so the sum of each probability of wining  is one

P(A)+P(B)+P(C)+P(D)=1

then we Know that the probability of Team A and B are the same, so

P(A)=P(B)

And that the  the probability that either team A or team C wins the tournament is 0.6, so P(A)+Pc)= 0,6, then P(C)= 0.6-P(A)

Also, we know that team C is twice as likely to win the tournament as team D, so P(C)= 2 P(D) so P(D) = P(C)/2= (0.6-P(A))/2

Now if we use the first formula:

P(A)+P(B)+P(C)+P(D)=1

P(A)+P(A)+0.6-P(A)+(0.6-P(A))/2=1

0,5 P(A)+0.9=1

0,5 P(A)= 0,1

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P(B)= 0,2

P(C)=0,4

P(D)=0,2

4 0
3 years ago
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