Answer:
sowy di ko alam
Step-by-step explanation:
search mo sa g.o.o.g.l.e
An=a1+d (n-1)
A1=200 since that's the first term that can be a multiple of 5
N=? That's what we need to find
An=1195 since that's the last multiple of 5 that we can use
D=5
Plug in
1195=200+5 (n-1)
-200 both sides
995=5 (n-1)
Distribute 5 to n-1
995=5n-5
+5 both sides
1000=5n
÷5 both sides
N=200 there are 200 multiples of 5 in between 199 and 1198
The trick here is that both times, part of the weight is soup
and part of the weight is the empty metal can.
1/2 soup + MTcan = 5
1/3 soup + MTcan = 4
Before going any further, it will make it a lot easier later if we change
the fractions in both equations to a common denominator:
1/2 = 3/6
1/3 = 2/6
3/6 soup + 1 MTcan = 5
2/6 soup + 1 MTcan = 4
Subtract the 2nd equation from the 1st one:
1/6 soup = 1
Multiply each side by 6 : <u>1 soup = 6</u>
Substitute this in the first equation:
1/2 soup + 1 MTcan = 5
1/2 ( 6 ) + 1 MTcan = 5
3 + 1 MTcan = 5
Subtract 3 from each side: <u>1 MTcan = 2</u>
The empty can weighs 2.
All the soup it can hold weighs 6.
A full can of soup weighs (2 + 6) = <em><u>8</u></em>
26 percent because there are a total of 200 gumballs. First you need to find the total amount of gumballs which is 200. You then know that 52/200 are red. Then you divide both numbers by two to get 26/100 which equals 26 percent.
Answer:
0.39
Step-by-step explanation:
0.27 TIMES 3 is 0.60+0.21=0.81 then 1.2-0.81=0.39
if you dont give me brainliest i will find and eat your soul from a milk jar :D
