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Bess [88]
3 years ago
11

5) A grocery store paid $147.98 for 7 crates of milk. This can be

Mathematics
1 answer:
gogolik [260]3 years ago
8 0
Answer: x= 21.14

Step by Step: $147.98 = 7x
147.98/7 =21.14
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3)
Wewaii [24]

Answer:

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

Step-by-step explanation:

Given -

\frac{1}{3} volume of sand in bucket is able to cover \frac{1}{9} area of the entire playground

Thus,

For covering  \frac{1}{9} unit area of the entire playground, the amount of sand required is equal to  \frac{1}{3}  of the total volume of sand in bucket

For covering  1 unit area of the entire playground, the amount of sand required is equal to

\frac{\frac{1}{3} }{\frac{1}{9} } \\\\\frac{1}{3}  * \frac{9}{1} \\\frac{9}{3}\\= 3

For covering  1 unit area of the entire playground, the amount of sand required is equal to volume of 3 buckets of sand.

4 0
3 years ago
I need helppp on my test and i can't get it wrongggg
Artyom0805 [142]

Answer:

Perimeter = 16x + 16

Area = 40x + 15

Step-by-step explanation:

Perimeter = the sum of all the side lengths

Perimeter = 2(8x+3) + 2(5) = 16x + 6 + 10 = 16x + 16

Area = product of base times height

Area = (8x+3)*5 = 40x + 15

6 0
2 years ago
Mathematical induction, prove the following two statements are true
adelina 88 [10]
Prove:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+n\left(\frac12\right)^{n-1}=4-\dfrac{n+2}{2^{n-1}}
____________________________________________

Base Step: For n=1:
n\left(\frac12\right)^{n-1}=1\left(\frac12\right)^{0}=1
and
4-\dfrac{n+2}{2^{n-1}}=4-3=1
--------------------------------------------------------------------------

Induction Hypothesis: Assume true for n=k. Meaning:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}=4-\dfrac{k+2}{2^{k-1}}
assumed to be true.

--------------------------------------------------------------------------

Induction Step: For n=k+1:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}

by our Induction Hypothesis, we can replace every term in this summation (except the last term) with the right hand side of our assumption.
=4-\dfrac{k+2}{2^{k-1}}+(k+1)\left(\frac12\right)^{k}

From here, think about what you are trying to end up with.
For n=k+1, we WANT the formula to look like this:
1+2\left(\frac12\right)+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}=4-\dfrac{(k+1)+2}{2^{(k+1)-1}}

That thing on the right hand side is what we're trying to end up with. So we need to do some clever Algebra.

Combine the (k+1) and 1/2, put the 2 in the bottom,
=4-\dfrac{k+2}{2^{k-1}}+\dfrac{(k+1)}{2^{k}}

We want to end up with a 2^k as our final denominator, so our middle term is missing a power of 2. Let's multiply top and bottom by 2,
=4+\dfrac{-2(k+2)}{2^{k}}+\dfrac{(k+1)}{2^{k}}

Distribute the -2 and combine the fractions together,
=4+\dfrac{-2k-4+(k+1)}{2^{k}}

Combine like-terms,
=4+\dfrac{-k-3}{2^{k}}

pull the negative back out,
=4-\dfrac{k+3}{2^{k}}

And ta-da! We've done it!
We can break apart the +3 into +1 and +2,
and the +0 in the bottom can be written as -1 and +1,
=4-\dfrac{(k+1)+2}{2^{(k-1)+1}}
3 0
3 years ago
A/75=15/100<br> help me in this :(
Svetach [21]

a / 75 = 15 / 100

100a = 75 * 15       [cross multiplication]

a = 11.25

i hope this helps!!! :D

4 0
3 years ago
Read 2 more answers
A.Calculate the water pressure of a solid at a depth of 75 cm from the clear surface of the water.
rusak2 [61]

Answer:

B.

Step-by-step explanation:

step by step sa na maka tulong

5 0
2 years ago
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