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leva [86]
2 years ago
8

6(1-5m) =

Mathematics
2 answers:
Delvig [45]2 years ago
6 0

Answer:

6(1-5m) = 6 − 30 m

3(4+3r) = 12 + 9 r

3(6r+8) = 18 r + 24

4(811+ 1+2) = 3256

-(-2-n) 7) = 14 + 7 n

-6(7k+11) = − 42 k − 66

-3(71+1) = − 216

-6(1 +116) = − 702

-10(a - 5) = − 10 a + 50

-3(1 + 2v) = − 3 − 6 v

-4(3r+2) = − 12 r − 8

(3 - 76)-2 = − 75

(-2018x+20) = − 2018 x + 20

(7 + 190)-15 = 182

(x + 1)14 =​ 14 x + 14

cupoosta [38]2 years ago
5 0
The answer is 14x +14
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Indirect Proof help! WILL MEDAL
Charra [1.4K]
The area of the rectangle:
A = Length x Width = JK x KL = 36 cm²
If JK ≥ 4 cm, we have to prove that KL ≤ 9 cm.
Answer:
Assume that a. KL > 9 cm.
Then the area of rectangle JKLM is greater than b. 36 cm²,
which contradicts the given information that c. side is at least 4 cm long.
So the assumption must be false. Therefore, d. KL ≤ 9 cm.
4 0
3 years ago
Which expression represents the following calculation?
alexdok [17]
SORRY IM LATE

TRY 5814

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3 0
2 years ago
What is the answer to 3*3
Vera_Pavlovna [14]
It’s 9 but are you serious
6 0
3 years ago
Read 2 more answers
The value of $y$ varies inversely as $\sqrt x$ and when $x=2$, $y=4$. What is $x$ when $y=1$?
Dovator [93]
$x=3$ I think that’s it... try that
4 0
3 years ago
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
3 years ago
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