3 years ago

Factorise p-q-x(q-p)

Mathematics

1 answer:

Fantom [35]3 years ago

8 0

Answer:

(1 + x)(p - q)

Step-by-step explanation:

Given

p - q - x(q - p) ← distribute parenthesis by - x

= p - q - qx + px ← rearrange terms in p and terms in q

= p + px - q - qx ( factor first/second terms and third/fourth terms )

= p(1 + x) - q(1 + x) ← factor out (1 + x) from each term

= (1 + x)(p - q)

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3 years ago

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3 years ago

Read 2 more answers

Can someone help me solve this question? It’s similar to the previous ones! Thank you!

luda_lava [24]

Answer:

$\boxed{\sf \ \ \ (-2x+-9)(1x+3)=-2x^2-15x-27 \ \ \ }$

the coefficient c is -27

Step-by-step explanation:

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$(-2x+-9)(1x+3)=(-2x-9)(x+3)=-2x(x+3)-9(x+3)=-2x^2-6x-9x-27\\=-2x^2-15x-27$

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3 years ago

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horsena [70]

Answer:

-2.5

Step-by-step explanation:

25/-10 = -2.5

20/-8 = 2.5

10/-4 = 2.5

-5/2 = 2.5

so the answer is -2.5

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2 years ago

Factorise p-q-x(q-p)​

Factorise p-q-x(q-p)