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irina1246 [14]
3 years ago
15

Given that Triangle KLM is congruent to Triangle RQP, what is the measurement of Side KL? Fill in the blank with only the numeri

cal answer. You do not have to include degrees.

Mathematics
2 answers:
____ [38]3 years ago
8 0
I think KL is 9.5 since the triangles are congruent
Burka [1]3 years ago
3 0

Answer:

Need more info.

Step-by-step explanation:

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Each cone of the hourglass has a height of 12 millimeters. The total height of the sand within the top portion of the hourglass
Harman [31]

The solution would be like this for this specific problem:

Volume of a cylinder = pi * r^2 * h 

Volume of a cone = 1/3 * pi * r^2 * h 

Total Height = 47

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Height of the cylinder = 35

If the top half is filled with sand, then:

volume (sand) = pi * 4^2 * 36

volume (cone) =  1/3 * pi * 4^2 * 12

Total volume = 1960.353816 cubic millimeters

353816 / (10 * pi) = 62.4 seconds.

It will take 62.4 seconds until all of the sand has dripped to the bottom of the hourglass.

7 0
3 years ago
on a certain planet, objects weight about 7/12 of what they weigh on earth. an object weights 13 5/12 pounds on the planet. solv
Cloud [144]
Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is <span>7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.


</span>
8 0
3 years ago
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