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2 years ago

Express the shaded area as a fraction, a decimal, and a percent of the whole.

Mathematics

2 answers:

nikitadnepr [17]2 years ago

8 0

Answer:

1/2

0.5

50%

Step-by-step explanation:

The square is spilt into 2 equal pieces, one out of the 2 is shaded therefore 1/2 is shaded. The decimal to represent the shaded area would be 0.5, as 1 times 1/2 = 0.5. As a percent the shaded area represents 50% as 1/2 times 100 (per cent = per hundred) is equivalent to 50.

I hope this helps :0).

horrorfan [7]2 years ago

6 0

1/2 = fraction. 1.2= decimal 12%= percent

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The length of a swimming pool is 10 ft shorter than twice the width. the length is 35 ft. what is the width

Hatshy [7]

Okay so we need to figure out the width of the swimming pool using the length, and we know the width is 10 ft shorter than twice the width. I believe the easiest way to do this would be to first do 35-10, and then divide it in half. That gives us 12.5. To check our work I'll do the problem 12.5+12.5+10=35.

The width of the swimming pool is 12.5 ft.

8 0

2 years ago

Point M (-3, 5) is translated using this rule. (x, y) ----> (x - 1, y) What are the coordinates of M'?

Nuetrik [128]

Answer:

The coordinates of point M' are $M'(x,y) = (-4, 5)$ .

Step-by-step explanation:

According to the statement, we have the following translation rule:

$M'(x,y) = M(x,y) + (-1, 0)$ (1)

Where:

$M(x,y)$ - Original point.

$M'(x,y)$ - Translated point.

$(-1, 0)$ - Translation vector.

If we know that $M(x,y) = (-3, 5)$ , then the coordinates of the point M' are:

$M'(x,y) = (-3,5) + (-1,0)$

$M'(x,y) = (-4, 5)$

The coordinates of point M' are $M'(x,y) = (-4, 5)$ .

5 0

2 years ago

Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m

strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

6C0 = 6!/6!0!

6C0 = 1

Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

3. Number of string with weight 1 is 6

Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

6C1 = 6!/(6-1)!1!

6C1 = 6!/5!1!

6C1 = 6

Hence, the number of string with weight 6

4. Number of string with weight 3 is 20

Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

5. Number of string with weight 5 is 6

Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

6. Number of string with weight 6 is 1

Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

6C6 = 1

Hence, the number of string with weight 6 is 1

7. Number of string with weight 7 is 0

Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

8 0

2 years ago

Ralph invested in a mutual fund and at the end of 20 years he has $14,300 in his account. If the mutual fund returned an average

Semenov [28]

Answer:

$\$5,500$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=20\ years\\ P=?\\ A=\$14,300\\r=8\%=8/100=0.08$

substitute in the formula above

$14,300=P(1+0.08*20)$

$14,300=P(2.6)$

$P=14,300/(2.6)$

$P=\$5,500$

7 0

3 years ago

Raphael works 12 hours each week. He earns £4 per hour. Tom saves 1/3 of earnings each week. How many weeks does it take Tom to

olga_2 [115]

Raphael works 12 hours each week. He earns £4 per hour. Tom saves 1/3 of earnings each week. How many weeks does it take Tom to save £80?

5 weeks

7 0

3 years ago