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olchik [2.2K]
3 years ago
11

Im really confused i hope this doesnt take to much time please help it would me so much to me.

Mathematics
1 answer:
katrin [286]3 years ago
6 0
Yes it is A I got it right
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The position function of a spaceship is below and the coordinates of a space station is r(t) r(t)=(3+t)i+(2+lnt)j+(7−4/t2+1)kand
bulgar [2K]

Answer:

The engine should be turned off at t = 1

Step-by-step explanation:

The detailed and step by step calculation is shown in the attachment below

6 0
3 years ago
How do you simplify 12 + 15 ÷ 3 × 6 – 4 step by step?
tatuchka [14]
Seperate the questions 12+15=25 ÷ by 3×6= 18-4= the answer
6 0
3 years ago
THE GRAPH IS BELOW THANKS :) Anika is on the crew to set up rides for the state fair. The crew does most of the setup on the day
Vaselesa [24]

Answer:

(a) We will form an equation of line from the points given (6,10) and (2,15)

Using:y-y_1=\frac{y_2-y_1}{x_2-x_1}\cdot (x-x_1)

On substituting the values in the formula above we will get the required equation of line.

y-10=\frac{15-10}{2-6}\cdot (x-6)

\Rightarrow y-10=\frac{5}{-4}\cdot (x-6)

On simplification we will get:

y=\frac{1}{4}(-5x+70)

(b) We need to tell at day 0 put x=0 in above equation:

y=\frac{1}{4}(-5\cdot 0+70)

y=70

Anika worked for 70 hours on the set up crew on the day the fair arrived at the fairgrounds day 0.

Now, we need to tell decrease per day which is equal to the slope of line

To find the slope compare the equation with general equation which is y=mx+c where m is slope

Here, in y=\frac{1}{4}(-5x+70)

m=\frac{-5}{4}  which is the decrease per day.


3 0
3 years ago
Find the exact value of tan 0
allsm [11]
Tan (0) is equal to 0
Sin (0) = 0
Cos (0) = 1

Tan = Sin/Cos
That means that Tan (0) = 0/1 or 0
3 0
3 years ago
Read 2 more answers
Can somebody explain how these would be done? The selected answer is incorrect, and I was told "Nice try...express the product b
trapecia [35]

Answer:

Solution ( Second Attachment ) : - 2.017 + 0.656i

Solution ( First Attachment ) : 16.140 - 5.244i

Step-by-step explanation:

Second Attachment : The quotient of the two expressions would be the following,

6\left[\cos \left(\frac{2\pi }{5}\right)+i\sin \left(\frac{2\pi \:}{5}\right)\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

So if we want to determine this expression in standard complex form, we can first convert it into trigonometric form, then apply trivial identities. Either that, or we can straight away apply the following identities and substitute,

( 1 ) cos(x) = sin(π / 2 - x)

( 2 ) sin(x) = cos(π / 2 - x)

If cos(x) = sin(π / 2 - x), then cos(2π / 5) = sin(π / 2 - 2π / 5) = sin(π / 10). Respectively sin(2π / 5) = cos(π / 2 - 2π / 5) = cos(π / 10). Let's simplify sin(π / 10) and cos(π / 10) with two more identities,

( 1 ) \cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos \left(x\right)}{2}}

( 2 ) \sin \left(\frac{x}{2}\right)=\sqrt{\frac{1-\cos \left(x\right)}{2}}

These two identities makes sin(π / 10) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and cos(π / 10) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}.

Therefore cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, and sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}. Substitute,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[\cos \left(\frac{-\pi }{2}\right)+i\sin \left(\frac{-\pi \:}{2}\right)\right]

Remember that cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting those values,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right]

And now simplify this expression to receive our answer,

6\left[ \left\frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}+i\left\frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}\right] ÷ 2\sqrt{2}\left[0-i\right] = -\frac{3\sqrt{5+\sqrt{5}}}{4}+\frac{3\sqrt{3-\sqrt{5}}}{4}i,

-\frac{3\sqrt{5+\sqrt{5}}}{4} = -2.01749\dots and \:\frac{3\sqrt{3-\sqrt{5}}}{4} = 0.65552\dots

= -2.01749+0.65552i

As you can see our solution is option c. - 2.01749 was rounded to - 2.017, and 0.65552 was rounded to 0.656.

________________________________________

First Attachment : We know from the previous problem that cos(2π / 5) = \frac{\sqrt{2}\sqrt{3-\sqrt{5}}}{4}, sin(2π / 5) = \frac{\sqrt{2}\sqrt{5+\sqrt{5}}}{4}, cos(- π / 2) = 0, and sin(- π / 2) = - 1. Substituting we receive a simplified expression,

6\sqrt{5+\sqrt{5}}-6i\sqrt{3-\sqrt{5}}

We know that 6\sqrt{5+\sqrt{5}} = 16.13996\dots and -\:6\sqrt{3-\sqrt{5}} = -5.24419\dots . Therefore,

Solution : 16.13996 - 5.24419i

Which rounds to about option b.

7 0
3 years ago
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