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kykrilka [37]
3 years ago
5

Solve one and three fourths times two fourths.

Mathematics
2 answers:
Marrrta [24]3 years ago
5 0

Answer:

1 3/4 * 2/4

= 7/4 * 2/4

= 7/4 * 1/2

= 7/8

KATRIN_1 [288]3 years ago
4 0

Answer:A/14/16

Step-by-step explanation:

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What is the difference between 1 and 2?<br><br> (a) 1<br> (b) Infinity<br> (c) Nothing<br> (d) 2
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The answer is a.

Difference means the amount of numbers between two numbers (subtraction).

2 - 1 = 1

Hope this helps!
4 0
3 years ago
What type of problems can always be solved using the law of cosines or sines?
laila [671]
Anytime you have a triangle (right triangles are preferred) where at least 2 angle measures and 1 side is known. Or, at least two sides and 1 angle measure. 

OR..... 3 sides or three angles are known. So, sines or cosines could be used at almost anytime to find the sides and angles of a triangle!
4 0
3 years ago
After driving 120 miles you completed 3/4 of the trip. How long was the entire trip
PtichkaEL [24]

Answer:

160

Step-by-step explanation:

120/3 = 40

40 x 4 = 160

May I have brainliest please? :)

7 0
3 years ago
Read 2 more answers
Chelsea works in a nearby building that is a 720
masya89 [10]

Answer:

I do not know what the rest of the problem is so I can not answer

8 0
4 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
3 years ago
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