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antiseptic1488 [7]
3 years ago
6

The data below shows the scores of 9 students on a history test...

Mathematics
2 answers:
iren2701 [21]3 years ago
7 0
Minimum is 63
Maximum is 99
Median is 79
Sladkaya [172]3 years ago
3 0
Minimum: 63
maximum: 99
median: 79

hope this helps
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The high school leadership team is having a car wash. They charge $5.50 for large cars and $4.00 for small cars . They had a suc
11Alexandr11 [23.1K]

Answer: 56 large cars and 86 small cars.

Step-by-step explanation:

Let's call:

l: the number of large cars.

s: the number of small cars.

Then, you can set up the following system of equations:

\left \{ {{l+s=142} \atop {5.50l+4.0s=652.50}} \right.

You can use the Elimination Method:

- Multiply the first equation by -4.0

- Add both equations.

- Solve for l.

\left \{ {{-4.0l-4.0s=-568} \atop {5.50l+4.0s=652.50}} \right.\\--------\\1.5l=84.5

l≈56

Substitute l=56 into one of the original equations and solve for <em>s:</em>

<em> </em>56+s=142\\s=142-56\\s=86

3 0
3 years ago
Draw a quick picture to show the number write how many tens and ones there are Edna has 82 stamps
ale4655 [162]
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8 0
3 years ago
If N = f(x) and f(x) = 3x^2 −x−5
harina [27]

Answer:

I really don't know so sorry

8 0
3 years ago
What relation does not have an initial value of 50
Mamont248 [21]
I guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50

4 0
3 years ago
Please help me with this!<br><br><br> show that {1,2} ⊆ {x|x^4 - x^3 - x^2 - 5x + 6 = 0}
Llana [10]

The set \{x\mid x^4-x^3-x^2-6x+6=0\} is the set of all values of x that are solutions to the given equation. So all you need to do is check whether x=1 and x=2 satisfy the equation.

x=1\implies 1^4-1^3-1^2-5+6=0

x=2\implies2^4-2^3-2^2-10+6=0

The equation holds, so both 1 and 2 are solutions, and hence \{1,2\} is a subset of the solutions.

6 0
3 years ago
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