All categories

3 years ago

Are there any vertical, complimentary, or any supplementary angles here ? And label for ex. 1 supplementary

Mathematics

1 answer:

kumpel [21]3 years ago

7 0

Supplementary: 1 and 2 & 3 and 4

Supplementary angles: A pair of angles whose sum is equal to 180°.

Vertical: 1 and 3 & 2 and 4

Vertical angles: A pair of opposite angles that are made by two intersecting lines.

Complimentary: None

Complimentary angles: A pair of angles whose sum is equal to 90°.

Hope this helps! :D

You might be interested in

hemraj made $135 for 9 hours of work. at the same rate, how many hours would he have to work to make $165?

ehidna [41]

Answer:

11 hrs

Step-by-step explanation:

so he made 135 for 9 hrs.....thats (135/9) = $ 15 an hr

so if he made 165, he would have to work (165/15) = 11 hrs <==

6 0

3 years ago

Kip bought one and four sixths pounds of toffee. He gave five sixths of a pound to his friend. How much toffee does Kip have lef

Ray Of Light [21]

Answer:

5/6

Step-by-step explanation:

1 4/6-5/6=?

1 4/6=10/6

10/6-5/6=5/6

6 0

3 years ago

Read 2 more answers

Which comparison is true? 38=36 38<36 38>36

mylen [45]

Answer:

38 > 36

it is true it shows that 38 is greater than 36

6 0

3 years ago

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constan

vitfil [10]

Answer:

$a = 6m/s^2$

Step-by-step explanation:

Given

When mass = 4kg; Acceleration = 15m/s²

Required

Determine the acceleration when mass = 10kg, provided force is constant;

Represent mass with m and acceleration with a

The question says there's an inverse variation between acceleration and mass; This is represented as thus;

$a\ \alpha\ \frac{1}{m}$

Convert variation to equality

$a = \frac{F}{m}$ ; Where F is the constant of variation (Force)

Make F the subject of formula;

$F = ma$

When mass = 4kg; Acceleration = 15m/s²

$F = 4 * 15$

$F = 60N$

When mass = 10kg; Substitute 60 for Force

$F = ma$

$60 = 10 * a$

$60 = 10a$

Divide both sides by 10

$\frac{60}{10} = \frac{10a}{10}$

$a = 6m/s^2$

Hence, the acceleration is  $a = 6m/s^2$ 

4 0

3 years ago

Solve each equation for θ, where 0° < θ < 90°. Answer correct to the nearest minute.

Assoli18 [71]

Answer:

Below in bold.

Step-by-step explanation:

sin θ = 4 cos θ

Note that tan θ = sin θ / cos θ so we

Divide both sides by cosθ:

tan θ = 4

θ = 75.96

= 75 degrees 58 minutes.

5 0

3 years ago