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Ivahew [28]
3 years ago
14

Help with question number 6 first person to asnwer gets branliest view attached image

Mathematics
1 answer:
Digiron [165]3 years ago
5 0
Arithmetic sequence with first term = -40, and common difference = -4.
nth term = (first term)+(n-1)(common difference) = -40-(n-1)4
49th term = -40-(48)4 = -232
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Simplify fully (2x-1)(2x+1)​
aleksandrvk [35]
4x^2 - 1 should be right
7 0
3 years ago
What is the slope of (3,5) and (1,3)
Maksim231197 [3]
(3,5)....x1 = 3 and y1 = 5
(1,3)....x2 = 1 and y2 = 3

slope formula : (y2 - y1) / (x2 - x1)
slope = (3 - 5) / (1 - 3) = -2/-2 = 1 <== slope is 1
7 0
3 years ago
Read 2 more answers
In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p
sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}

We know that formula for permutations is given as

_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}

On substituting the given values in the formula we get,

{_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}

=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\&#10;\\&#10;=35\cdot 34\cdot 33=39270

Therefore, there are 39270 ways in which prizes can be awarded.


6 0
3 years ago
A train leaves at 17.22 and arrives at its destination at 18.14.
sattari [20]

Answer:

64.6 km/h

Step-by-step explanation:

18:14 = 18h 14'

1h = 60'

18h = 17h + 60'

18h14' = 17h + 60' ´14' = 17h 74'

then:

17h 74'

-17h 22'

= 0h 52'

the train travelled 56km at 52 minutes

56km/52minutes

1 hour = 60 minutes

52 minutes = 52/60 = 0.86667 hours

then:

56km/52minutes = 56km/0.86667hours

= 64.615 km/hours

5 0
2 years ago
Your friend, Susannah, manages a sandwich shop. She collects data on the number of turkey sandwiches sold per day for a week. Ex
ExtremeBDS [4]

Susannah's data are illustration of measure of central tendencies

<u>(a) The mean</u>

To calculate the mean, she needs to divide the total number of turkey sandwiches sold, by the number of days.

The total is:

\mathbf{Total = 73 +88+85+88+99+134+129}

\mathbf{Total = 696}

The number of days is:

\mathbf{Day = 7}

So, the mean is:

\mathbf{Mean =\frac{Total}{Days}}

\mathbf{Mean =\frac{696}{7}}

\mathbf{Mean =99.4}

Hence, the mean number of turkey sandwiches sold is 99.4

<u>(b) The median</u>

To calculate the median, she needs to arrange the data in ascending or descending order, then select the middle item.

In ascending order, we have: 73, 85, 88, 88, 99, 129, 134

The middle item is 88

So:

\mathbf{Median = 88}

Hence, the median number of turkey sandwiches sold is 88

<u>(c) The mode</u>

This is the data that occurs most.

From the dataset, 88 appears twice (more than others).

So:

\mathbf{Mode = 88}

Hence, the mode number of turkey sandwiches sold is 88

<u>(d) The range</u>

This is the difference between the highest and least data

From the dataset,

The highest is 134, and the least is 73

So:

\mathbf{Range =134 - 73}

\mathbf{Range =61}

Hence, the range of turkey sandwiches sold is 61

The measure that would be most helpful is the median, because it is not affected by outliers.

Read more about measures of central tendencies at:

brainly.com/question/5495004

6 0
3 years ago
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