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Sladkaya [172]
3 years ago
7

Question 11 options: the lengths of human pregnancies are normally distributed with a mean of 268 days and a standard deviation

of 15 days. what is the probability that a pregnancy lasts at least 300 days?
Mathematics
1 answer:
Ber [7]3 years ago
3 0
Think of (or draw) a standard normal curve with mean 268 days and std dev 15 days.

Calculate the z-score for 300 days:

       300-268          32
z = -------------- = --------- = 2.13
           15                15

Now find the area under the curve to the right of z = + 2.13.  Alternatively, find the area under the curve to the left of this z and subtract the result from 1.00.

I used my TI-83's DISTR function normalcdf( to calculate the area to the right of 300 days:

normalcdf(300,infinity, 268, 15) = 0.016, or about 0.02.

Only about 2% of pregnancies will last 300 days or longer.
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Answer:

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Step-by-step explanation:

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18 < -12x + 6               Start isolating 'x'

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18 - 6 < -12x                  '+ 6' is cancelled out on the right side

12 < -12x                    Subtracted 6 from 18 on the left side

12/-12 < -12x/-12                    Divide both sides by -12

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-1 < x                    Answer

x > -1             Standard formatting puts variable on the left side

6 0
2 years ago
Sarah has 273 feet of wire to make bead necklaces. If each necklace requires 1 2/3 feet of wire, how many necklaces can she make
o-na [289]

Oh boy, here we go again

First we must convert  1 2/3 to an improper fraction.  By doing this, we get 5/3  (3/3 + 2/3)

So now we have 273 /  5/3

To divide this easier we can do something that when I learned it was called (keep, change, flip)  which basically means keep the first fraction, change the sign from division to multiplication, and flip the second fraction

This now turns into:  273/1 * 3/5

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vitfil [10]
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Ierofanga [76]

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