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marysya [2.9K]
3 years ago
7

calculate the amount of property tax due. Tax rate:$41. 50 per $1,000. Assessed value:$148,00. What's the amount of property tax

due?​
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

Taxes owed = taxable assessment x property tax rate per thousand ... Generally, the property tax rate is expressed as a percentage per $1,000 of assessed value. ... rate = $50 per $1,000 of taxable assessed value; Tax bill for property

Step-by-step explanation:

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The density of a fluid is given by the empirical equation rho=70.5 exp(8.27 X 10^-7 P) where rho is density (lbm/ft^3) and P is
jasenka [17]

Answer:

(a) The unit of 70.5 is lbm/ft^3 and the unit of 8.27×10^-7 is in^2/lbf

(b) density = 0.1206g/cm^3

(c) rho = 0.1206exp(8.27×10^-7P)

Step-by-step explanation:

(a) The unit of 70.5 is the same as the unit of rho which is lbm/ft^3. The unit of 8.27×10^-7 is the inverse of the unit of P (lbf/in^2) because exp is found of a constant. Therefore, the unit of 8.27×10^-7 is in^2/lbf

(b) P = 9×10^6N/m^2

rho = 70.5exp(8.27×10^-7× 9×10^6) = 70.5exp7.443 = 70.5×1.71 = 120.6kg/m^3

rho = 120.6kg/m^3 × 1000g/1kg × 1m^3/10^6cm^3 = 0.1206g/cm^3

(c) Formula for rho (g/cm^3) as a function of P (N/m^2) is

rho = 0.1206exp(8.27×10^-7P) (the unit of 0.1206 is g/cm^3)

5 0
3 years ago
A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he
Nina [5.8K]

The maximum units is 200 and , Total revenue is $8,000

<u>Step-by-step explanation:</u>

Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:

We have following function as R(x)=80x-0.2x^ 2 . Let's differentiate this and equate it to zero to find value of x for which the function is maximum!

⇒ R(x)=80x-0.2x^ 2

⇒ \frac{d(R(x))}{dx}=\frac{d(80x-0.2x^ 2)}{dx}

⇒ \frac{d(R(x))}{dx}=\frac{d(80x)}{dx}-\frac{d(0.2x^ 2)}{dx}}

⇒ 0=80-2x(0.2)

⇒ \frac{80}{0.4}=x

⇒ x=200

Now , Value of function at x=200 is :

⇒ R(200)=80(200)-0.2(200)^ 2

⇒ R(200)=16000-8000

⇒ R(200)=8000

Therefore , The maximum units is 200 and , Total revenue is $8,000

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C, or the last photo, shows a reflection.
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Answer:

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Given figure is of a rhombus.

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Therefore,

m \angle \: 1 = 120 \degree

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