Ask question

Ask question

All categories

2 years ago

15

Acrylic spheres with diameters of 24 cm are used to make award trophies. How much acrylic is needed to make 15 trophies? Use 3.1

4 for π . Complete Steps 1-3 in order.

1 answer:

choli [55]2 years ago

6 0

1. 27,129.6

2. 7,234.56

3. r=12

hope this helps sry if ther wrong pls don’t be mad if there right u r welcome

You might be interested in

niah works as a retail sales clerk earning $18,000 per yer. she plans to go to school for medical billing that has a median sala

OLEGan [10]

Investment: cost of her education + salary as sales clerk during two years

Investment = 18,000 (2) + 20,000 = 36,000 + 20,000 = 56,000

Time to recover investment = 56,000/35,000 = 1.6

In less than two years, after she starts to work Niah will have recoverd her investment.

3 0

2 years ago

Read 2 more answers

|x - 7| - |x - 2| = 3

rewona [7]

|x-7| - |x-2| = 3

x = 3

7 0

2 years ago

A cement truck pours cement into a container in the shape of a cylinder with a radius of 4 feet. The height, h, of the cement in

julsineya [31]

Answer:

2009.6 and 13824 minutes and 230.4 hours

Step-by-step explanation:

v=3.14 x 4 x 2 x 80= 2009.6

7 0

2 years ago

What is the expansion of (3+x)^4

Vlad1618 [11]

Answer:

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

Step-by-step explanation:

Considering the expression

$\left(3+x\right)^4$

Lets determine the expansion of the expression

$\left(3+x\right)^4$

$\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i$

$a=3,\:\:b=x$

$=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i$

Expanding summation

$\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}$

$i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0$

$i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1$

$i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2$

$i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3$

$i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

$=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4$

as

$\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81$

$\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x$

$\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2$

$\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3$

$\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4$

so equation becomes

$=81+108x+54x^2+12x^3+x^4$

$=x^4+12x^3+54x^2+108x+81$

Therefore,

$\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81$

6 0

2 years ago

Line "AB" and line "CD" are perpendicular and intersect at point P. What is the measure of angle APC?

Step2247 [10]

Answer:

APC is 90 degrees

Step-by-step explanation:

When lines intersect and are perpendicular. that means the angle of intersection is 90 degrees.

APC is 90 degrees

7 0

3 years ago

Read 2 more answers