Answer:
meter,liter and gram metric system
Answer:
a(n) = -351+8(n-1)
Step-by-step explanation:
This is an arithmetic sequence. Each new term is equal to the sum of the previous term and 8.
The expression you want is a(n) = -351+8(n-1)
Step-by-step explanation:
RS bisects PQ at T. PQ bisects RS at T.
<u>prove</u>: Triangle PTS congruent Triangle QTR
<h3>Statements..............................Reasons</h3>
(1) RS bisects PQ at T.................(1) Given
(2) PQ bisects RS at T.................(2) Given
(3) angle PST ≅ angle QRT........(3) supplements of congruent angles
(4) TS ≅ TR......................(4) Converse of Base Angles Theorem
(5) angle PTS ≅ angle QTR.........(5) Subtraction Property of Equality
(6) Triangle PTS ≅ Triangle QTR...(6) Angle side angle
Hope it's help you..... ^_^❤️
Starting from
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take the first derivative using the power and chain rules:


Now take the second derivative:


Optionally, you can condense the second derivative a bit by factoring out
, which gives



9514 1404 393
Answer:
- 89 in a restaurant
- 45 in a car
- 59 at home
Step-by-step explanation:
Let r, c, h represent the numbers of meals eaten in a restaurant, car, and at home, respectively. The problem statement tells us of the relations ...
r + c + h = 193
-r + c + h = 15
r + 0c -h = 30
Add the last two equations:
(-r +c +h) +(r -h) = (15) +(30)
c = 45
Add the first two equations:
(r + c + h) +(-r + c + h) = (193) +(15)
2c +2h = 208
h = 104 -c = 59 . . . . solve for h, substitute for c
The last equation can be used to find r.
r = 30 +h = 30 +59 = 89
89 meals are eaten in a restaurant; 45 meals in a car; and 59 at home.