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Tamiku [17]
3 years ago
14

Find the circumference and the area of a circle with radius 5 yd

Mathematics
1 answer:
slavikrds [6]3 years ago
6 0

Answer:

C = 10(pi) yards

A = 25(pi) yards

Step-by-step explanation:

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5 0
3 years ago
Given that P = (5, 8) and Q = (6, 9), find the component form and magnitude of vector PQ.
masha68 [24]
((x2-x1),(y2-y1))
((6-5),(9-8))
Component form: (1,1)
(1^2+1^2)^(1/2)
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6 0
2 years ago
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Please help me with this question....
AVprozaik [17]

Answer:

63.63 {m}^{2}

Step-by-step explanation:

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7 0
3 years ago
Plzzzzz help will give brain and points!!! Explain why a quadratic equation with a positive discriminant has two real solutions,
NISA [10]

Answer:

The given equation is -2x^2 = -8x + 8

This can be rewritten as 2x^2 - 8x + 8 = 0

Here the value of a =2, b = -8 and c = 8

Discriminant = b^2 - 4ac

Now plug in the above values in the discriminant, we get

= (-8)^2 - 4*2*8

= 64 - 64

= 0

Here the discriminant is 0, so we will get one real root.

The discriminant is equal to 0, which means the equation has one real number solution.

Hope this will helpful.

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5 0
3 years ago
For each equation, determine whether it represents a direct variation, an inverse variation, or neither.
SSSSS [86.1K]

we know that in direct variation as x increase y also increases.

in indirect variation x decreases y increase and vice versa.

in part a we have x at top (numerator ) and y at denominator it mean indirect variation (as x increases y decreases).

to find k we know that for indirect variation xy=k

if we rewrite the equation x=9/y we get xy=9

which mean k=9 .

in part b we have 4xy=20 if we simplify this equation we get

xy=20/4=5

so here if we rewrite in terms of x.

we get x=5/y which represents indirect variation.

and we know xy=k

we have xy=5 .so k=5

8 0
3 years ago
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