Find the circumference and the area of a circle with radius 5 yd
1 answer:
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The correct option is: Option (B) 
Explanation:
First thing is that the difference between each number in the series with the next number is 5. It means it must be the multiple of 5. There are two options that contain multiples of 5: Option B and Option D. Now in the option D, the upper limit is 6. If we put 6 in the expression: 5(6)-2, the last term would be 28. However in the series given in the question, the last term is 33. Hence 5(7) - 2 = 35 - 2 = 33 which is Option B.
When i=1: 5(1)-2 = 3
When i=2: 5(2)-2 = 8
When i=3: 5(3)-2 = 13
.
.
When i=7: 5(7)-2 = 35-2 = 33
Hence the correct option is (B).
Explanation:
First thing is that the difference between each number in the series with the next number is 5. It means it must be the multiple of 5. There are two options that contain multiples of 5: Option B and Option D. Now in the option D, the upper limit is 6. If we put 6 in the expression: 5(6)-2, the last term would be 28. However in the series given in the question, the last term is 33. Hence 5(7) - 2 = 35 - 2 = 33 which is Option B.
When i=1: 5(1)-2 = 3
When i=2: 5(2)-2 = 8
When i=3: 5(3)-2 = 13
.
.
When i=7: 5(7)-2 = 35-2 = 33
Hence the correct option is (B).
Answer:
Step-by-step explanation:
charge q1 is placed at x = 1.90 m and the charge q2 is placed at y = 1.15 m
here, the charge enclosed in a sphere is zero as the radius of sphere is 0.625 m which is less than the x = 1.90 m and y = 1.15 m. So by the Gauss's theorem,
where q is the charge enclosed, as the charge enclosed is zero so the electric flux is zero.