Answer:
The equation of the perpendicular line 't' is 3x+y =0
Point slope form y = mx +C
y = - 3x
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given equation s =
and given point (1,-3)
The equation of the perpendicular line
![y =\frac{x+30}{3}](https://tex.z-dn.net/?f=y%20%3D%5Cfrac%7Bx%2B30%7D%7B3%7D)
⇒ 3 y = x+30
⇒ x - 3y +30 =0
<u><em>Step(ii):-</em></u>
<em>The perpendicular line of the given straight line 's'</em>
<em> b x -ay +k=0</em>
⇒ -3x -y +k=0
This line is passing through the point (1,-3)
-3(1)-(-3)+k=0
k =0
The equation of the perpendicular line -3x-y =0
<u><em>Final answer:-</em></u>
The equation of the perpendicular line 3x+y =0
Point slope form y = mx +C
y = - 3x