Can you please solve this I don't understand perpendicular lines
1 answer:
Answer:
The equation of the perpendicular line 't' is 3x+y =0
Point slope form y = mx +C
y = - 3x
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given equation s = and given point (1,-3)
The equation of the perpendicular line
⇒ 3 y = x+30
⇒ x - 3y +30 =0
<u><em>Step(ii):-</em></u>
<em>The perpendicular line of the given straight line 's'</em>
<em> b x -ay +k=0</em>
⇒ -3x -y +k=0
This line is passing through the point (1,-3)
-3(1)-(-3)+k=0
k =0
The equation of the perpendicular line -3x-y =0
<u><em>Final answer:-</em></u>
The equation of the perpendicular line 3x+y =0
Point slope form y = mx +C
y = - 3x
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Step-by-step explanation:
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