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goblinko [34]
3 years ago
6

3 equivalent ratios for 14/2

Mathematics
2 answers:
Bezzdna [24]3 years ago
6 0
7/1, 21/3, 28/4 you just use multiples!
Nimfa-mama [501]3 years ago
5 0

Answer:

7/1

21/3

532/76

Step-by-step explanation:

You might be interested in
What is the slope of the line graphed below?
Vlad [161]

Answer:

A

Step-by-step explanation:

Use rise over run. The graph rises by 9 units between the 2 points and runs 3 units on the x axis.

Rise/ run = \frac{9}{3}, which can be simplified to 3.

The slope is 3.

7 0
3 years ago
Read 2 more answers
S
Rudiy27

Answer:

<h2>(3, -2)</h2>

Step-by-step explanation:

Put the coordinates of the points to the inequality and check:

y < -1/2x + 2

for (2, 3) → x = 2, y = 3

3 < -1/2(2) + 2

3 < -1 + 2

3 < 1     FALSE

============================

for (2, 1) → x = 2, y = 1

1 < -1/2(2) + 2

1 < -1 + 2

1 < 1    FALSE

============================

for (3, -2) → x = 3, y = -2

-2 < -1/2(3) + 2

-2 < -1.5 + 2

-2 < 0.5      TRUE

============================

for (-1, 3) → x = -1, y = 3

3 < -1/2(-1) + 2

3 < 1/2 + 2

3 < 2 1/2      FALSE

6 0
4 years ago
How do the graphs of f(x)=x^3 and g(x)=(1/2 x)^3 relate?
Novay_Z [31]

Answer:

A. G(x) is a horizontal stretch of f(x) by a factor of 2.

3 0
3 years ago
How do I solve this
anastassius [24]
\bf \cfrac{x+2}{x^2+6x-7}    so, that function is "defined", ok, what values of "x" are not in the domain, namely, what values can "x" take on and not make the function "undefined", well,  you know, if we end up with a 0 at the denominator, like   \bf \cfrac{x+2}{0}    then, we'd have an "undefined" expression...so... any values of "x" that make the denominator 0, are not really the ones we want, and thus they'd be excluded from the domain.


so, hmm which are those? let's check, let's set the denominator to 0, and solve for "x".

\bf x^2+6x-7=0\implies (x+7)(x-1)=0\implies x=&#10;\begin{cases}&#10;-7\\&#10;1&#10;\end{cases}&#10;\\\\\\&#10;\textit{let's check, } x=-7\quad \cfrac{(-7)+2}{(-7)^2+6(-7)-7}\implies \cfrac{-5}{49-42-7}\implies \cfrac{-5}{0}&#10;\\\\\\&#10;x=1\quad \cfrac{(1)+2}{(1)^2+6(1)-7}\implies \cfrac{3}{1+6-7}\implies \cfrac{-3}{0}
7 0
4 years ago
Which point on the number line indicates a number that is less than 9.1 and greater than 6.5
Dahasolnce [82]

Answer:


Step-by-step explanation:


8 0
3 years ago
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