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IrinaK [193]
3 years ago
5

Here is a list of numbers.

Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0
Awnser:

a) Tanya didn’t order them from the smallest number to the biggest number

b) 32.5 i’m not sure if that can be cause it isn’t a whole number i haven’t done mean median mode and rang in a long time sorry

EXPLAINATION:

order your numbers from least to greatest and then start crossing them off from each end if there are two numbers in the middle then add them up and divide them by two in this case we added 32 and 33 it was 65 then I divided 65 by 2 it was 32.5
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how many integers from 100 to 999, inclusive, don't include the numbers 2,4,6,8? PLS HELP I WILL MARK BRAINLIEST
UNO [17]

Answer:

243

Step-by-step explanation:

999-100= 899 integers

200s 400s 600s 800s excluded so 400 numbers excluded

899 - 400 = 499

20s 40s 60s 80s which are 40 integers x 4 = 160

499 - 160 = 339

2s 4s 6s 8s which are 4 integers x 6 x 4 ( 4 from each 100 ) = 96

339 - 96 = 243 integers

7 0
2 years ago
Uh Expanded form pls? 4.02 x 10^5
Vera_Pavlovna [14]

Answer:

4.02 x 10 x 10 x 10 x 10 x 10

Step-by-step explanation:

The part that needs expanding is the exponent. Since it is to the power of 5 there needs to be 5 written out 10's, all multiplied.

4.02 x 10 x 10 x 10 x 10 x 10

4 0
3 years ago
Read 2 more answers
5y − x =10 , solve the equation for y?
jek_recluse [69]

Answer:

-2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Is answer choice D correct help please ??
SpyIntel [72]
O wpuld say that d is correct
4 0
3 years ago
Read 2 more answers
The sum of a number times 8 and 21 is less than -16.
vodka [1.7K]

Hello.

First of all, let the number be t.

8 times t can be written like this:

\mathrm{8t}

Notice that the number is before the variable and the times sign (×) is not there.

We can write it as 8×t, but we usually write it as 8t.

The sum of means we add:

8t+21

Now, "less than" is "<" :

\mathrm{8t+21 < -16}

Therefore, the answer is

\mathrm{8t+21 < -16}

I hope it helps.

Have a nice day.

\boxed{imperturbability}

7 0
2 years ago
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