42/558 is what you write to show the expression 42 divided by 558
First, the formula for the average of a data set must be defined. It is calculated by adding all the numbers in the data set and then dividing the sum by the number of data. In this case, the average is set to be equal to $400 with the total number of data being 3, with the September expenditure set as an unknown, x. The equation is then set-up to be: 400 = (401.5 + 250 + x)/3. Thus, Joshua can spend as much as $ 548.5 to be able to have the same average as in his second quarter expenditure.
Question:
What is the greatest common factor (GCF) of 24 and 40?
Answer:
8
Step-by-step explanation:
I suppose you mean

Then

and the difference quotient is

If it's the case that <em>x</em> ≠ 3, then (<em>x</em> - 3)/(<em>x</em> - 3) reduces to 1, and you would be left with
Answer:
Continuous
Step-by-step explanation:
Its continous because after each day you take the same amount away and due to that it will be continous.