All categories

3 years ago

Plz help will give magical powers if answered

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

4 0

For n to n' it is a translation 2 units down, for m to m' it is a translation 2 units down and 2 to the right

natulia [17]3 years ago

3 0

It is shifted 2 down and 2 right.

You might be interested in

18 × 5 × 10 × 9 × 7

otez555 [7]

18×5×10×9×7 IS 56,700

4 0

3 years ago

Read 2 more answers

Find the direct relationship between y and x . <br> x=e^2t<br> y=e^t

olya-2409 [2.1K]

Answer:

x = y²

Step-by-step explanation:

Given

x = $e^{2t}$ and y = $e^{t}$

Note that

x = $e^{2t}$ = $e^{t}$ × $e^{t}$ = y²

Thus x = y²

5 0

3 years ago

Read 2 more answers

a new computer costs $450. What is the final price of the computer if it is in sale for 30% off and you must pay the 7% sales ta

zzz [600]

Answer:

$337.05

Step-by-step explanation:

450 x (1- 0.3)= $315

$315 x (1+0.07)= $337.05

4 0

3 years ago

I need help with this one

sdas [7]

I cannot see it all is their something you could do to help me help you?

5 0

3 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago