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Fantom [35]
3 years ago
11

Tell whether the triangle is a right triangle. Show Work.​

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

This is not a right triangle because the hypotenuse is less than the two sides and aren't equal when following the Pythagorean thm

Step-by-step explanation:

To confirm if a triangle is a right triangle, we must use the Pythagorean thm

a^2 + b^2 = c^2

23^2 + 11.4^2 = 21.2^2

529 + 129.96 = 449.44

658.96 ≠ 449.44

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I need help with number 33!!!
sveta [45]

Area of Big Rectangle                                     Area of Small Rectangle

A = L x w                                                           A = L x w

 = (25 + 2w)(10 + 2w)                                           = 25 x 10

 =   250 + 50w + 20w + 4w²                               = 250

       Big - Small  

74 = 250 + 70w + 4w² - 250

74 = 4w² + 70w

0 = 4w² + 70w - 74

   = 2(2w² + 35w - 37)

  = 2[2w² -2w  |  +37w - 37]

  = 2[2w(w - 1) |  +1(w - 1)]

  = 2(2w + 1)(w - 1)

0 = 2                                   0 = 2w + 1                                     0 = w - 1

FALSE so disregard          w = -1/2                                         w = 1

                                         NEGATIVE so disregard

Answer: 1 meter

5 0
3 years ago
CAN SOMEONE HELP ME!!!!!!!!!!!!!!!
Crazy boy [7]

Answer: 150 min

Step-by-step explanation:

2 hours = 120 min, 120 + 30 min = 150 min

3 0
3 years ago
Read 2 more answers
ME ajudem porfavor não aguento mais, tá muito dificil
mihalych1998 [28]

Answer:

say it in English plZz

I can't understand Spanish or whatever ur saying sorry

8 0
3 years ago
The total stopping distance T for a vehicle is T = 2.5x + 0.5x 2 , where T is in feet and x is the speed in miles per hour. Appr
Kobotan [32]

Answer:

%  change in stopping distance = 7.34 %

Step-by-step explanation:

The stooping distance is given by

T = 2.5 x + 0.5 x^{2}

We will approximate this distance  using the relation

f (x + dx) = f (x)+ f' (x)dx

dx = 26 - 25 = 1

T' =  2.5 + x

Therefore

f(x)+f'(x)dx = 2.5x+ 0.5x^{2} + 2.5 +x

This is the stopping distance at x = 25

Put x = 25 in above equation

2.5 × (25) + 0.5× 25^{2} + 2.5 + 25 = 402.5 ft

Stopping distance at x = 25

T(25) = 2.5 × (25) + 0.5 × 25^{2}

T(25) = 375 ft

Therefore approximate change in stopping distance = 402.5 - 375 = 27.5 ft

%  change in stopping distance = \frac{27.5}{375} × 100

%  change in stopping distance = 7.34 %

6 0
3 years ago
Write a word phrase that can be represented by b – 6.
Aleonysh [2.5K]
D , the answer is "six less than a number b"
4 0
3 years ago
Read 2 more answers
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