Answer:
-615.12
Step-by-step explanation:
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P = how many cars Peter has
j = how many cars Jade has
a = how many cars Andre has
p x 4 = how many cars Andre has (36 model cars)
>>>TO FIND HOW MANY MODEL CARS PETER HAS:
p x 4 = 36
36 / 4 = 9
your equation to find how many model cars Peter has is:
36 / 4 = 9
So, Peter has 9 model cars.
>>>TO FIND HOW MANY MODEL CARS JADE HAS:
36 / 4 = how many cars Peter has (9)
Now, you are given the info that Jade has THREE TIMES (3x) as many cars as Peter already.
So, your equation for this one is:
9 x 3 = 27
So Jade has 27 model cars.
---- Jade has 27 model cars.
---- Andre has 36 model cars.
---- Peter has 9 model cars.
equation for a. 36 / 4 = p
equation for b. 9 x 3 = j
Answer:
Step-by-step explanation:
Any time you have compounding more than once a year (which is annually), unless we are talking about compounding continuously, you will use the formula

Here's what we have:
The amount after a certain time that she has in the bank is 4672.12; that's A(t).
The interest rate in decimal form is .18; that's r.
The number of times the interest compounds is 12; that's n
and the time that the money is invested is 3.5 years; that's t.
Filling all that into the formula:
Simplifying it down a bit:
Raise 1.015 to the 42nd power to get
4672.12 = P(1.868847115) and divide to get P alone:
P = 2500.00
She invested $2500.00 initially.
Answer:
yes
Step-by-step explanation:
y < 2x +4
6 < 2·5 +4
6 < 14