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statuscvo [17]
3 years ago
14

Write an equation to match this graph.

Mathematics
1 answer:
Gekata [30.6K]3 years ago
6 0

Answer:

y - 5 = 5(x - 1)

Step-by-step explanation:

Two points on the graph are (1, 5) and (7, 35).  Going from the first to the second, we see x (the 'run') increasing by 6 and y (the 'rise') increasing by 30.  Hence the slope of this line is m = rise / run = 30/6, or 5.

Using the point-slope equation, we get

y - 5 = 5(x - 1)

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3 years ago
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OABC is a tetrahedron and OA=a, OB=b, and OC=c. The point P and Q are such that OA =AP and 2OB = BQ. The point M is a midpoint o
kondaur [170]

Given

.OABC is a tetrahedron

OA=a, OB=b, and OC=c.

point P and Q are such that OA =AP and 2OB = BQ

point M is a midpoint of PQ.

Find AB ,PQ, CQ ,QM ,MB ,OM in terms of a, b, and c.

To proof

we proof this by using the Triangle law of vector addition

when two vectors are represented by two sides of a triangle in magnitude and direction taken in same order then third side of the third side of that triangle represents in magnitude and direction the resultant of the vectors.

by using the diagram as shown below

 \vec{OA}=\vec{a}, \vec{OB}=\vec{b}\\\vec{OP}=2\vec{a},\vec{OQ}=3\vec{b}

\vec{OA}+\vec{AB}=\vec{OB}\\\vec{AB}=\vec{b}-\vec{a}

\vec{OP}+\vec{PQ}=\vec{OQ}\\\vec{PQ}=3\vec{b}-2\vec{a}

\vec{OC}+\vec{CQ}=\vec{OQ}\\\vec{CQ}=3\vec{b}-2\vec{c}\\\vec{QM}=-\frac{1}{2}\vec{PQ}\\

\vec{QM}=\vec{a}-\frac{3}{2}\vec{b}\\\vec{OM}=\vec{OQ}+\vec{QM}

\vec{OM}=\vec{a}+\frac{3}{2}\vec{b}\\\vec{MB}=-\vec{a}-\frac{1}{2}\vec{b}

hence proved




     



6 0
3 years ago
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Musya8 [376]

Answer:

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Answer:

700 minutes or 11.67 hours

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8.75*80=700

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3 years ago
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