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3 years ago

What is the remainder when P(x)=2x3-3x2-5x-6 is divided by (x-3)

Mathematics

1 answer:

balu736 [363]3 years ago

4 0

Answer:

remainder = 6

Step-by-step explanation:

Hope it helps.....

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Help omg I’m struggling ‍

Harrizon [31]

I believe the answer would b y^2 x^3•12/10

7 0

3 years ago

. Here is an equation 2x + 9 = -15. Write three different equations that have the same solution as 2x + 9 = -15. Show or explain

Anettt [7]

Answer:

1. $x-3=-15$
2. $2x=-24$
3. $2x-3=-27$

Step-by-step explanation:

Given the following question:

$2x+9=-15$

To find three equations that have the same solution as the given equation we have to first solve the equation.

$2x+9=-15$
$9-9=0$
$-15-9=-24$
$2x=-24$
$2x\div2=x$
$-24\div2=-12$
$x=-12$

Equation one:
$x-3=-15$
$-3+3=0$
$-15+3=-12$
$x=-12$

Equation two:
 $2x=-24$
$2x\div2=x$
$-24\div2=-12$
$x=-12$

Equation three:
$2x-3=-27$
$-3+3=0$
$-27+3=-24$
$-24\div2=-12$
$x=-12$

Hope this helps.

4 0

2 years ago

Please help me , thank you

Mama L [17]

Answer:

Step-by-step explanation:

The range are the values that y can take.

From the graph we can see that all defined values of y are below the x- axis

Thus range is y < 0 → b

5 0

3 years ago

Kirby is four miles from the train station, from which a train is due to leave in 56 minutes. Kirby is walking along at 3 mph, a

Luda [366]

Let's assume that Kirby walks with a speed
$v_1 = 3 mph$
for a time $t_1$ , and that he runs with a speed
$v_2 = 12 mph$
for a time $t_2$ .

The total time available for Kirby to catch the train is:
$t=56 min = 0.93 h$
and this must be equal to the sum of the two times t1 and t2:
$0.93 = t_1 + t_2$

The distance Kirby should cover is
$S=4 m$
and this should be equal to the sum of the distances covered by walking and by running:
$4 = S_1 + S_2 = v_1 t_1 + v_2 t_2 = 3 t_1 + 12 t_2$

So we have a system of 2 equations:
$0.93 = t_1 + t_2$
$4 = 3 t_1 + 12 t_2$

If we solve the system, we find:
$t_1 = 0.80 h = 48 min$
$t_2 = 0.13 h = 8 min$

So, Kirby needs to run at least for 8 minutes in order to catch the train.

6 0

3 years ago

Invasive species often experience exponential population growth when introduced into a new environment. Zebra mussels are an inv

Oliga [24]

Answer:

If ‘a’ is the initial population of the Zebra mussels, then every six months, the population of Zebra mussels quadruples, i.e. it becomes 4a. In t years, i.e. in 2t intervals of 6 months each, the population of Zebra mussels can be computed with the help of a geometric series a, ar, ar2, ar3, …. arn-1 ( the series being finite with n terms) where a is the 1st term , r is the common ratio and n is the number of terms in the series..

Here, in 2t years, there will be 2t + 1 terms in the geometric series including the initial term. Thus in the above series, a = 10, r = 4 and n = 2t + 1. Then the population of the Zebra mussels after 2t years is the (2t +1)st term of the geometric series I.e. 10* ( 42t)

In 15 months, t = 15/12 = 1.25. Then the population of Zebra mussels after 15 months will be 10*(42.5 ) = 10 * 25 = 320

If after t years, the population of the Zebra mussels become 1 million , then we have

1000000 = 10 * (42t) or, 100000= 42t or,105 = 42t Taking logarithms of both sides, we have 5 log 10 = 2t log 4 or, t = (5log10)/(2log4) = 5/1.20 years or (5/1.20) * 12 months = 50 months, i.e. 4 years and 2 months.

Step-by-step explanation:

8 0

3 years ago

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