Rearrange the ODE as


Take

, so that

.
Supposing that

, we have

, from which it follows that


So we can write the ODE as

which is linear in

. Multiplying both sides by

, we have

![\dfrac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]=x^3e^{x^2}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5Be%5E%7Bx%5E2%7Du%5Cbigg%5D%3Dx%5E3e%5E%7Bx%5E2%7D)
Integrate both sides with respect to

:
![\displaystyle\int\frac{\mathrm d}{\mathrm dx}\bigg[e^{x^2}u\bigg]\,\mathrm dx=\int x^3e^{x^2}\,\mathrm dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%5Cfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5Be%5E%7Bx%5E2%7Du%5Cbigg%5D%5C%2C%5Cmathrm%20dx%3D%5Cint%20x%5E3e%5E%7Bx%5E2%7D%5C%2C%5Cmathrm%20dx)

Substitute

, so that

. Then

Integrate the right hand side by parts using



You should end up with



and provided that we restrict

, we can write
Answer:
y=mx+b :)
Step-by-step explanation:
Answer:
The least number of hours that she would have to work is 11.
Step-by-step explanation:
First, make the equation be "12.75x +100=235". Then, subtract 10 from both sides of the equation. You would get
"12.75x= 135". Then, divide both sides of the equation by 12. 75x, and the equation turns out to say, "x=10.59".
To find the scale factor divide the bigger measurement by the smaller one.
You did number 17. 42 / 3 = 14 so your scale factor is 14, option D.
For number 18, 48 / 6 = 8 so option A.
<span>x =<span>−<span><span>2<span> and </span></span>y </span></span></span>=<span>−<span>2. Hope this helps</span></span>