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Inga [223]
3 years ago
13

 please help me ahhh im doing 8th grade math with pythagorean theorem

Mathematics
2 answers:
bixtya [17]3 years ago
7 0

Step-by-step explanation:

The pythagorean theorem is the sum of the two legs squares equal the hypotenuse squared.

The hypotenuse is the longest side so 3.5 is our hypotenuse.

Apply formula to see of true.

{a}^{2}  +  {b}^{2}  =  {c}^{2}

{2.5}^{2}  +  {3}^{2}  =  {3.5}^{2}

6.25 + 9 = (3.5  {}^{2}) {?}

15.25 = 12.25 {?}

So it isn't a triangle since they aren't equal

yuradex [85]3 years ago
6 0
I think it isnt a right triangle, but im sorry if thats wrong
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<h3>How much water would the gardener need to water the whole garden?</h3>

Here we know that the gardener needs 1/3 of a liter of water to water 2/7 of a garden.

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mestny [16]

Answer:

An equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is:

  • y=-6x+7

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where m is the slope and b is the y-intercept

Given the equation

6x+y=6

Writing in the slope-intercept form of the line equation

y = -6x + 6

comparing with the slope-intercept form of the line equation

y = mx+b

Thus, the slope of line = m = -6

We know that the parallel lines have the same slopes.

Thus, the slope of the parallel line is also -6.

As the line passes through the point (2,−5).

Thus, using the point-slope form of the line equation

y-y_1=m\left(x-x_1\right)

where m is the slope and (x₁, x₂) is the point

substituting the values m = -6 and the point (2,−5)

y-y_1=m\left(x-x_1\right)

y - (-5) = -6 (x - 2)

y+5=-6\left(x-2\right)

subtract 5 from both sides

y+5-5=-6\left(x-2\right)-5

y=-6x+7

Therefore, an equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is:

  • y=-6x+7
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