All categories

3 years ago

Please help me, its due today!!!

Mathematics

1 answer:

zlopas [31]3 years ago

8 0

Answer:

$7$

Step-by-step explanation:

So we have the expression:

$|3x-1|$

And we want to evaluate it for x=-2.

So, substitute -2 for x:

$|3(-2)-1|$

Multiply:

$=|-6-1|$

Subtract:

$=|-7|$

The absolute value of a negative is positive. So:

$=7$

And we're done!

You might be interested in

Where does the line y = 3x + 5 cross the y-axis?

crimeas [40]

C: at y=5

The formula is y=mx+b (b meaning the y-intercept) so that +5 is where your y-intercept is gonna be!

7 0

3 years ago

A Yamaha dirt bike has a sticker price of

Rasek [7]

Answer:

1353.13

Step-by-step explanation:

1250*.0825= 103.125+1250= 1353.125

then round to the hundredths place to get 1353.13

You have to get 8.25% to a fraction to be able to multiply move the decimal point to the left twice.

4 0

3 years ago

Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t

dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: $(x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14$

<u>Area of the big rectangle</u>: $(x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99$

The difference is: $11x+85$

$( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85$

You can solve this question just by looking at the graph.

a) The height is 4 meters.

$f(d)=h=-2d^2+7d+4$

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

$f(0)=h=-2(0)^2+7(0)+4$

$h=4$

The height is 4 meters.

b) 9 meters.

For $d=1$

$f(1)=h=-2(1)^2+7(1)+4$

$f(1)=h=-2+7+4$

$h=9$

b) The ball travels 4 meters.

But to calculate it, it is when $h=0$

$0=-2d^2+7d+4$

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

$V=\pi r^2h$

$V=\pi (2.5)^2 \cdot 5$

$V=31.25 \pi$

$V_{c} \approx 98.17 \text{ m}^3$

The volume of the sphere:

$V=\frac{4}{3} \pi r^2$

$V_{s} \approx 65.4 \text{ m}^3$

The volume of the capsule is approximately $163.57 \text{ m}^3$

3 0

3 years ago

One hypotenuse and one leg of a right triangle have lengths 61 and 11. Find the length of the other leg

atroni [7]

If the length is the same as one leg, than all the other legs should be the same exact dimensions, legs can not be different measurements by height. Hope that this help you!

5 0

3 years ago

Use the factor theorem to determine if (x-2) and (x+4) are factors of f(x)=x^3-6x^2+11x-6

Sergio [31]

Hope this can help.
I think x-2 is factor of f(x) but x+4 is not.

7 0

2 years ago