(11x+10)(x+-1)
(X+1)(11x+-10)
We use the given data above to calculate the volume of gasoline that is being burned per minute by commercial airplanes.
Amount burned of 1 commercial airplane = <span>3.9 × 10³ ml of gasoline per second
Number of airplanes = </span><span>5.1 × 10³ airplanes
We calculate as follows:
</span> 3.9 × 10³ ml of gasoline per second / 1 airplane (5.1 × 10³ airplanes)(60 second / 1 min ) = <span>1.2 x 10^9 mL / min</span>
Ok so lets say we have a system of equations:
y = x + 1
x + y = 5
All you would do is plug in what is equal to the variable so:
x + x + 1 = 5
Then you would just simplify and solve
2x + 1 = 5
-1 -1
_________
2x = 4
-- --
2 2
x=2
A.
100%=all
so if 25% is dark and the rest is milk then
dark+milk=all
25%+milk=100%
minus 25% both sides
milk=75%
so
if milk chocolate=3lb then
3lb=75%
divide by 3
1lb=25%=dark chocolate
oops, I didn't use an equation
hmm
ratios and things
75%=milk
25%=dark
so we got
for m=pounds of milk chocolate
and d=dark chocolate
m/d=72/25 or m/d=3 and
m=3
duh
3/d=3
3=3d
1=d
B. 1 lb dark chocolate
.2041 miles! please look at my picture for steps on how to do it