Answer:
3 salad = 3 lettuce + 6 tomatoes + 9 three carrots
Coefficients: 3, 6, 9
Explanation:
1 salad = 1 lettuce + 2 tomatoes + 3 three carrots
<em>Multiply all the coefficients of 1 salad by 3:</em>
3(1 salad) = 3(1 lettuce + 2 tomatoes + 3 three carrots)
<em>Expand the equation:</em>
3 salad = 3 lettuce + 6 tomatoes + 9 three carrots
Answer:
Explanation:
You need to know one piece of information for these problems. That is as follows:
There are 6.02 x 10^23 atoms in a mole of atoms or 6.02 x 10^23 molecules in a mole of molecules (actually there are 6.02 x 10^23 in a mole of anything).
So in 3.161 x 10^21 molecules of CO2 there are 3.161 molecules x (1 mole CO2/6.02 x 10^23 molecules CO2)= ?? moles CO2. Then multiply that by 2 to find the moles of O in CO2.
The others are done th same way.
By the process of Nuclear Fission:
1) We Generate Electricity. - If the process is controlled, then we can do this. It's very better way to generate electricity. 'cause of it's many advantages, all nation wants to enhance their electricity production through this mean.
2) We Create explosive. - Again, with the help of nuclear fission we can create certain helpful bombs like Atom Bomb which will help us in war.
Hope this helps!
Answer:
5.22 atm
Explanation:
The following data were obtained from the question:
Number of mole (n) = 2 moles
Volume (V) = 10 L
Temperature (T) = 45 °C
Pressure (P) =?
Next, we shall convert 45 °C to Kelvin temperature. This can be obtained as follow:
Temperature (K) = Temperature (°C) + 273
T (K) = T (°C) + 273
T (°C) = 45 °C
T(K) = 45 °C + 273
T (K) = 318 K
Finally, we shall determine the pressure of the gas by using the ideal gas equation as shown below:
Number of mole (n) = 2 moles
Volume (V) = 10 L
Temperature (T) = 318 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =.?
PV = nRT
P x 10 = 2 x 0.0821 x 318
Divide both side by 10
P = (2 x 0.0821 x 318) /10
P = 5.22 atm
Therefore, the pressure of the gas is 5.22 atm
Answer:
305 g of CO₂
3.77 × 10⁵ kJ
Explanation:
Let's consider the global reaction for photosynthesis.
6 CO₂(g) + 6 H₂O(l) → C₆H₁₂O₆(g) + 6 O₂(g) ΔHrxn = 2802.8 kJ
<em>A 1.70 lb sweet potato is approximately 73% water by mass. If the remaining mass is made up of carbohydrates derived from glucose (MW = 180.156 g/mol), how much carbon dioxide (MW = 44.01 g/mol) was needed to grow this sweet potato?</em>
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Let's consider the following relations:
- The potato is 100%-73%=27% glucose by mass.
- 1 lb = 453.59 g.
- 6 moles of CO₂ produce 1 mole of glucose.
- The molar mass of glucose is 180.156 g/mol.
- The molar mass of carbon dioxide is 44.01 g/mol.
Then, for a 1.70 lb potato:
<em>How much light energy does it take to grow the 1.70 lb. sweet potato if the efficiency of photosynthesis is 0.86%?</em>
<em />
According to the enthalpy of the reaction, 2802.8 kJ are required to produce 1 mole of glucose. Then, for a 1.70 lb potato:
