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3 years ago

How are dogs born? (10 points)

Chemistry

1 answer:

snow_lady [41]3 years ago

6 0

Answer:

Most puppies are born head first but some come tail first. Puppies are born inside a thin sac, which the mother will remove, enabling them to breathe. After each puppy, your dog should pass an afterbirth (placenta), which they often eat.

Explanation:

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1What is ""Fremy's salt""? Write the molecular formula of Fremy's salt. Write the structure of the product obtained from phenol.

EastWind [94]

Answer and Explanation:

The Fremy salt is a chemical compound its chemical name is disodium nitrosodisuphonate

The molecular formula of the Fremy salt is $K_2NO(SO_3)_2$

When phenol is treated with Fremy salt in presence of water then benzoquinone is formed

$C_2H_5OH\rightarrow C_6H_4O_2$ ( in presence of Fremy salt and water)

5 0

3 years ago

7. How many moles are in 5 x 10 2 atoms of gold?

goblinko [34]

Answer:

8.3028894e-22

Explanation:

5x10^2 atoms/1 x 1 mol/6.022x10^23

7 0

3 years ago

An atom in the ground state contains a total of 5 electrons 5 protons and 5 neutrons. Which Lewis electron-dot diagram represent

Luba_88 [7]

I don't know if you didn't gave a picture choice or if i didn't get the picture.
But lets call this atom A. Electron dot formula doesn't require Neutron and Protons, its main concern is valance elections.

So atom A has 5 electrons which means 2,3 it has 3 valance electrons. Its dot formula will become
:A.

I hope this helped.

7 0

3 years ago

Does adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent, a lesser extent, or a greater e

igor_vitrenko [27]

Answer:

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water <em><u>to the same extent</u></em> by adding 1 mol of $C_06H_{12}O_6$ to 1 kg of water.

Explanation:

1) Moles of NaCl , $n_1=1 mol$

Mass of water = m= 1 kg = 1000 g

Moles of water = $n_2=\frac{1000 g}{18 g/mol}=55.55 mol$

Vapor pressure of the solution = $p$

Vapor pressure of the pure solvent that is water = $p_o=17.5 Torr$

Mole fraction of solute(NaCl)= $\chi_1=\frac{n_1}{n_1+n_2}$

$\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}$

$\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}$

$p=17.19 Torr$

The vapor pressure for the NaCl solution at 17.19 Torr.

2) Moles of sucrose , $n_1=1mol$

Mass of water = m = 1 kg = 1000 g

Moles of water = $n_2=\frac{1000 g}{18 g/mol}=55.55 mol$

Vapor pressure of the solution = $p'$

Vapor pressure of the pure solvent that is water = $p_o=17.5 Torr$

Mole fraction of solute ( glucose)= $\chi_1=\frac{n_1}{n_1+n_2}$

$\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}$

$\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}$

$p'=17.19 Torr$

The vapor pressure for the glucose solution at 17.19 Torr.

p = p' = 17.19 Torr

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent by adding 1 mol of $C_06H_{12}O_6$ to 1 kg of water.

3 0

3 years ago

How would you separate a mixture of 4-tert-butylphenol and 2- chlorobenzoic acid? Explain the detailed steps including the choic

Sergeu [11.5K]

The a mixture of 4-tert-butylphenol and 2- chlorobenzoic acid is separate by the by using bicarbonate solvent.

When solution of bicarbonate is added in mixture of 4-tert-butylphenol and 2- chlorobenzoic acid then 2- chlorobenzoic acid form a carboxylate ion whereas 4-tert-butylphenol is underacted and filtered out.

Since, only 2- chlorobenzoic acid which is acid is convert into its conjugate base by solution of bicarbonate in mixture of 4-tert-butylphenol and 2- chlorobenzoic acid .

However, phenol is less acidic than carboxylic acid. Both phenol and carboxylic acid is soluble in organic solvent . At that point as the phenol isolates as an oil, one needs to cool the blend in an ice shower to encourage crystallization

to learn more about 4-tert-butylphenol

brainly.com/question/5274368

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7 0

2 years ago