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mrs_skeptik [129]
4 years ago
5

How many oxygen atoms in 3.161*10^21 molecules of CO2?

Chemistry
1 answer:
vfiekz [6]4 years ago
3 0

Answer:

Explanation:

You need to know one piece of information for these problems. That is as follows:

There are 6.02 x 10^23 atoms in a mole of atoms or 6.02 x 10^23 molecules in a mole of molecules (actually there are 6.02 x 10^23 in a mole of anything).

So in 3.161 x 10^21 molecules of CO2 there are 3.161 molecules x (1 mole CO2/6.02 x 10^23 molecules CO2)= ?? moles CO2. Then multiply that by 2 to find the moles of O in CO2.

The others are done th same way.

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How many liters of oxygen are released from the decomposition of 36.5 grams of hydrogen peroxide at STP?
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Answer:

12 liters of oxygen are released from the decomposition of the peroxide.

Explanation:

The hydrogen peroxide is decomposed by this reaction:

2 H₂O₂ (l) → 2 H₂O (l) + O₂ (g)

Molar mass H₂O₂ = 34 g/m

Moles of peroxide: 36.5 g / 34 g/m = 1.07 moles

Ratio is 2:1, so 2 moles of peroxide will be decomposed in 1 mol of oxygen (exactly the half)

1.07 moles of peroxide will be decomposed in the half of moles, 0.54 moles

Let's apply the Ideal Gases law Equation to solve the volume

1 atm . V = 0.54 mol . 0.082 .273K

V = (0.54 mol . 0.082 .273K) / 1 atm → 12L

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