Area shaded = Area big circle- Area of small circle;
200 pi= pi•(2x)^2 -pi•6^2;
200pi= pi•4x^2 -pi•36;
200pi=pi•4(x^2 -9) divide both sides by 4pi;
50=x^2 -9; So x=sqrt(59)~7.68cm
√x + 9 - 4 = 1
√x + 5 = 1
√x = -4
√x = √-4
x = 2i
answer:
△JKI ≅ △CED
step-by-step explanation:
- like i mentioned before, they look similar and fulfill the SSS triangle theorem (this time's the theorem is different only)
Answer:
B
Step-by-step explanation:
Hope this helps! have a great day!
Like you would put 0.5 or 1. or 1.5 as like 1/2 or 1/3 and you plot negatives first
