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Leona [35]
3 years ago
5

The money raised By $15 candy is approximately What percent of The total money raised from The candy sale

Mathematics
2 answers:
Monica [59]3 years ago
7 0
Can you explain it a bit more?
liubo4ka [24]3 years ago
5 0

This is an incomplete question. Refer to the chart given in the attached image.

With respect to this image, what percent of total money is raised from the candy sale?

Let x be the percent of total money raised from the candy sale.

Total money raised from candy sale is:

Money raised by $1 candy = 100 \times \$1 =\$ 100

Money raised by $5 candy= 25 \times \$5 =\$ 125

Money raised by $10 candy = 20 \times \$10 =\$ 200

Money raised by $15 candy = 15\times \$5 =\$ 75

Total money raised from candy sale = \$(100+125+200+75)

= \$ 500.

According to the question,

Money raised by sale of $15 candy = x % of Total money raised from candy sale

75 = x \% of 500

75 =\frac{x}{100} \times 500

75 = 5x

x = \frac{75}{5}

x =15%

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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

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