Given, the ratio of blocks A, B, C,D are in the ratio 4:7:3:1
Let us consider the common ratio to be ‘x’.
So, toy blocks with alphabet A is 4x and
toy blocks with alphabet B is 7x and
toy blocks with alphabet C is 3x and
toy blocks with alphabet D is x
Again, the number of ‘A’ blocks is 50 more than the number of ‘C’ blocks.
As no. of ‘A’ and ‘C’ blocks are 4x and 3x respectively.
So,
4x=50 + 3x
x=50
Thus, the number of ‘B’ blocks is 7x = 7(50) = 350
350 is the required number.
Split
into two component segments,
and
, parameterized by


respectively, with
, where
.
We have


where 
so the line integral becomes



Answer:
467,059,500
Thank you for the points! And this is really easy, just add :))
Answer:
131
Step-by-step explanation:
Using proportion,
If Out of 550 calculators = 6 are defective,
Then out of 12000 calculators = ? are defective

= 21.8 * 6
= 130.8 ≈ 131
∴ Approximately 131 calculators are defective