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Elena-2011 [213]

3 years ago

7

Help please !!!!!!!!!!!!!!11

1 answer:

Finger [1]3 years ago

6 0

Answer: 1.9 per year this is the answer

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What is the solution to N < 5

Daniel [21]

Answer:

I need more information about the question please so I can happily help you.

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2 years ago

Which equation of the least squares regression line most closely matches the data set? yˆ=3.5x−6921.2 yˆ=5.5x+52 yˆ=−2.2x+13.8 y

konstantin123 [22]

A graphing calculator finds the regression line to be
y = 5.5x + 52

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2 years ago

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The factory used to produce 126 articles a day. As a result of retooling, production increased to 189 articles a day. What was t

NARA [144]

Answer: The answer is 50%.

Step-by-step explanation: Given that the factory produces 126 articles in a day. After retooling, the production of the articles increased and they started producing 189 articles in a day. We need to calculate the percent increase in labour productivity.

We have,

Percent Increase in labour productivity will be equal to the percent increase in the number of articles.

Increase in the number of articles after retooling = 189 - 126 = 63.

Therefore, percent increase in the number of articles is given by

$p=\dfrac{63}{126}\times 100\%=\dfrac{100}{2}\%=50\%.$

Thus, the labour productivity increased by 50%.

8 0

3 years ago

F(x) = 14 - 0.5<br> f(30) =

serg [7]

Answer:

13.5

Step-by-step explanation:

4 0

3 years ago

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Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6

ElenaW [278]

<h2>Answer</h2>

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

Or as ordered pairs: $(\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)$

<h2>Explanation</h2>

Lets solve our system of equations step by step

$x^2+y^2=6$ equation (1)

$x^2-y=6$ equation (2)

1. Solve for $x^2$ in equation (2)

$x^2-y=6$

$x^2=6+y$ equation (3)

2. Replace equation (3) in equation (1) and solve for $y$

$x^2+y^2=6$

$6+y+y^2=6$

$y^2+y=0$

$y(y+1)=0$

$y=0$ or $y=-1$

3. Replace the values of $y$ in equation (3) and solve for $x$

- For $y=0$

$x^2=6+y$

$x^2=6$

$x=\sqrt{6}$ or $x=-\sqrt{6}$

- For $y=-1$

$x^2=6+y$

$x^2=6-1$

$x^2=5$

$x=\sqrt{5}$ or $x=-\sqrt{5}$

So, the solutions of our system of equation are:

$x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1$

6 0

2 years ago

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