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MA_775_DIABLO [31]
3 years ago
14

Pls help I’ll brainlest

Mathematics
1 answer:
Natali [406]3 years ago
8 0

Answer:

C. 5.8 × 10^{-5}

Step-by-step explanation:

0.000058

4 zeros

4 + 1 = 5

5.8 × 10⁻5

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Find the variation constant and an equation of variation where y varies directly as x and y=24 when x=3.
Kay [80]

Answer:

8

Step-by-step explanation:

y=x, y=kx, k is a constant, k/x=y/x, k=y/x, k=24/3, k=8

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3 years ago
Convert each degrees minutes seconds into decimal degrees <br> 351°41’142”
pav-90 [236]

Answer:

351.7227778°

Step-by-step explanation:

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Inverse functions always go in the same direction as the original function. true or false?
zavuch27 [327]
False , that’s why they are inverse
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4 years ago
Which set of lengths are the side lengths of a right triangle? (9,15,17) (14,23,25) (20,30,40) (15,36,39)
goldfiish [28.3K]

Answer:

(15, 36, 39)

Step-by-step explanation:

Using pythagoreas formula: A^2 * B^2 = C^2

so a=15, b=36, c=39

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6 0
3 years ago
Evaluate the integral Integral ∫ from (1,2,3 ) to (5, 7,-2 ) y dx + x dy + 4 dz by finding parametric equations for the line seg
n200080 [17]

\vec F(x,y,z)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k

is conservative if there is a scalar function f(x,y,z) such that \nabla f=\vec F. This would require

\dfrac{\partial f}{\partial x}=y

\dfrac{\partial f}{\partial y}=x

\dfrac{\partial f}{\partial z}=3

(or perhaps the last partial derivative should be 4 to match up with the integral?)

From these equations we find

f(x,y,z)=xy+g(y,z)

\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

f(x,y,z)=xy+h(z)

\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=3z+C

f(x,y,z)=xy+3z+C

so \vec F is indeed conservative, and the gradient theorem (a.k.a. fundamental theorem of calculus for line integrals) applies. The value of the line integral depends only the endpoints:

\displaystyle\int_{(1,2,3)}^{(5,7,-2)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz=\int_{(1,2,3)}^{(5,7,-2)}\nabla f(x,y,z)\cdot\mathrm d\vec r

=f(5,7,-2)-f(1,2,3)=\boxed{18}

8 0
3 years ago
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