According to Newton's third law, the two forces in a force pair act

a sample of cobalt (specific heat of Co=0.418J/G C )at 100.0 C is dropped into a calorimeter containing 500.0 mL of water at 21.

Alex17521 [72]

Answer:

$m_{Co}=6998g=7.0kg$

Explanation:

Hello there!

In this case, according to this equilibrium temperature problem, we can set up the following equation to relate the mass, specific heat and temperature change:

$Q_{Co}=-Q_{w}\\\\m_{Co}C_{Co}(T_f-T_{Co})=-m_{w}C_{w}(T_f-T_{w})$

Thus, we solve for the mass of cobalt as shown below:

$m_{Co}=\frac{-m_{w}C_{w}(T_f-T_{w})}{C_{Co}(T_f-T_{Co})} \\\\m_{Co}=\frac{-500.00g*4.184J/g\°C(67.1\°C-21.1\°C)}{0.418J/g\°C(67.1\°C-100\°C)} \\\\m_{Co}=6998g=7.0kg$

Best regards!

7 0

3 years ago

When c2h4 molecules polymerize, the name of the polymer formed is

Gnoma [55]

<span>When c2h4 molecules polymerize, the name of the polymer formed is (b) Polyethylene. This is because the compound C2H4 is ethylene (common name) or ethene (IUPAC name) and polymerizing it would produce polyethylene. The other names are not applicable for C2H4.

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7 0

3 years ago

Determina la masa atómica promedio del cobre teniendo en cuenta que este elemento se encuentra en la naturaleza en forma de dos

beks73 [17]

Answer:

63.5474U.M.A. es la masa atómica promedio del cobre

Explanation:

La masa atómica promedio de un átomo es definida como la suma de las masas de los isótopos multiplicada por su abundancia. Para el caso del cobre que tiene dos isótopos:

Cu = Masa 65Cu*Abundancia + Masa 63Cu*Abundancia

Reemplazando con los valores dados en el problema:

Cu = 62.9298U.M.A.*0.6909 + 64.9278U.M.A.*0.3091

Cu = 63.5474U.M.A. es la masa atómica promedio del cobre

6 0

3 years ago

use the density formula to solve the following problems. a sample of a substance has a volume of 60.5mL and a density of 1.20mL.

svetlana [45]

Answer:

mass of substance =50.4 g

Explanation:

Using the density formula;

Density = mass of substance / volume of substance

Therefore, making mass subject of the density formula,

mass of substance = volume of substance / density of substance

volume of substance = 60.5 mL, density = 1.20 g/mL ( since common units of density is either g/cm³ or g/mL)

mass of the substance = 60.5 mL / 1.20 g/mL

mass of substance = 50.4 g

3 0

3 years ago

If a certain mass of mercury has a volume of 0.002 m2 at a temperature of 20 celsius, what will be the volume of 50 celsius?

SIZIF [17.4K]

Answer: 0.0022m3

Explanation:

Initial volume of mercury V1 = 0.002m3 (note that the unit of volume can be cm3, m3, dm3 or liters)

Initial temperature T1 = 20°C

Convert temperature in Celsius to Kelvin

( 20°C + 273°C = 293K)

Final temperature T2 = 50°C

( 50°C + 273°C = 323K)

Final volume V2 = ?

According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.

Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2

0.002/293 = V2/323

To get the value of V2, cross multiply

V2 = (323 x 0.002) / 293

V2 = 0.646 / 293

V2 = 0.0022 m3

Thus, the new volume of mercury will be 0.0022m3

3 0

4 years ago