Answer:
Enthalpy change for the dissolution of the unknown solid = 4.6 Kj/mole
Explanation:
Using Q = m x Cs x ΔT ................................(1)
where Q = Amount of heat absorbed
m = Mass of solution
Cs = Specific heat capacity of solution
ΔT = Change in temperature
Given Density of solution = 1.20 g/ml
And volume of solution = 150 ml
Mass of solution = density x volume
= 1.2 x 150
= 180 g
From equation (1)
Q = 180 x 4.18 x 19.2 = 14446.08 = 14.4 Kj
So, ΔH of the dissolution of the unknown solid = 
= 
= 4.6 kj/mole
Answer:
The molarity of a solution is "25 M".
Explanation:
The given values are:
Moles of solute,
= 12.5 g
Volume of solution,
= 500 mL
i.e.,
= 0.5 L
Now,
The molarity will be:
= 
On substituting the values, we get
= 
= 
Answer:
0.054 moles of carbon dioxide will be produced
Explanation:
Step 1: Data given
Number of moles oxygen = 0.085 moles
Step 2: The balanced equation
2C8H18 + 25O2 → 16CO2 + 18H2O
Step 3: Calculate moles of carbon dioxide
For 2 moles octane we need 25 moles oxygen gas to produce 16 moles carbon dioxide gas and 18 moles water vapor
0.0544
For 0.085 moles O2 we'll have 16/25 * 0.085 = 0.054 moles CO2
0.054 moles of carbon dioxide will be produced
Answer:
the right answer is : d
Explanation:
Because temperature is a cinetic factor.
d, one atom of oxygen and two atoms of hydrogen
