Which statement accurately describes the rock layers

Describe where a hydrogen bond can form among water molecules.

stiv31 [10]

Answer:

In water hydrogen bonding formed between partially negative oxygen and partially positive hydrogen atoms.

Explanation:

Hydrogen bond is a partially electrostatic attraction between hydrogen (H), which is bonded to a more electronegative atom such as nitrogen (N), oxygen (O) or fluorine (F), and another adjacent atom bearing a lone pair of electrons.

In water molecule hydrogen and oxygen have difference in electronegativity, due to which dipoles are form. One is partial positive on hydrogen atom and other is partial negative on oxygen atom. The electrostatic attraction occur between two oppositely charged poles which is known as hydrogen bonding.

4 0

3 years ago

What is Br mass number?

Fofino [41]

Name Bromine

Symbol Br

Atomic Number 35

Atomic Mass 79.904 atomic mass units

Number of Protons 35

Number of Neutrons 45

Number of Electrons 35

Melting Point -7.2° C

Boiling Point 58.78° C

Density 3.119 grams per cubic centimeter

Normal Phase Gas

Family Halogens

Period 4

Cost $4.90 per 100 grams

3 0

3 years ago

What are the enviromental factors of cornavirus

maksim [4K]

Well, I know one. A positive: decreasing pollution because most people are in quarantine and not outside.

4 0

3 years ago

) If I have 223.4 grams of iron, how many moles of iron do I have?

Natalija [7]

Answer:

Number of moles of iron are 4 mol.

Explanation:

Given data:

Mass of iron = 223.4 g

Number of moles = ?

Solution:

Molar mass of iron = 55.85 g/mol

Formula:

Number of moles = mass/molar mass

Number of moles = 223.4 g/ 55.85 g/mol

Number of moles = 4 mol

3 0

3 years ago

A 100.0 mL solution containing 0.923 gof maleic acid (MW=116.072 g/mol) is titrated with 0.265 M KOH. Calculate the pH of the so

Vlad1618 [11]

Answer:

pH = 9,57

[M²⁻] = 7,948x10⁻²M

[HM⁻] = 4x10⁻⁵M

[H₂M] = 0M

Explanation:

The moles of maleic acid presents in the solution are:

0,923g× $\frac{1mol}{116,072g}$ =7,952x10⁻³moles of H₂M

60,0mL of 0,265M KOH are:

0,0600L× $\frac{0,265mol}{1L}$ =0,0159 moles of KOH

The reactions of maleic acid (H₂M) and then with HM⁻ are:

H₂M + KOH → HM⁻ + H₂O + K⁺ (1)

HM⁻ + KOH → M²⁻ + H₂O + K⁺ (2)

For a complete transformation of H₂M in HM⁻ there are necessaries 7,952x10⁻³moles of KOH. As the moles of KOH are 0,0159 moles, the restant moles are:

0,0159 - 7,952x10⁻³ = 7,948x10⁻³ moles of KOH

By (2), the moles produced of M²⁻ are the same as moles of KOH, 7,948x10⁻³ moles, and moles of HM⁻ are:

7,952x10⁻³ - 7,948x10⁻³ = 4x10⁻⁶ moles of HM⁻

Using Henderson-Hasselbalch formula:

pH = pka + log₁₀ [M²⁻] /[HM⁻]

pH = 6,27 + log₁₀ 7,948x10⁻³ / 4x10⁻⁶

pH = 9,57

The moles of M²⁻ are 7,948x10⁻³ and volume of the solution is 0,1000L,

[M²⁻] = 7,948x10⁻²M

Moles of HM⁻ are 4x10⁻⁶:

[HM⁻] = 4x10⁻⁵M

And there is not H₂M:

[H₂M] = 0M

I hope it helps!

8 0

3 years ago