Answer:
Read this passage from Through the Looking-Glass.
She looked at the Queen, who seemed to have suddenly wrapped herself up in wool. Alice rubbed her eyes, and looked again. She couldn't make out what had happened at all. Was she in a shop? And was that really—was it really a SHEEP that was sitting on the other side of the counter? Rub as she could, she could make nothing more of it: she was in a little dark shop, leaning with her elbows on the counter, and opposite to her was an old Sheep, sitting in an arm-chair knitting, and every now and then leaving off to look at her through a great pair of spectacles.
“What is it you want to buy?” the Sheep said at last, looking up for a moment from her knitting.
“I don't QUITE know yet,” Alice said, very gently. “I should like to look all round me first, if I might.”
“You may look in front of you, and on both sides, if you like,” said the Sheep: “but you can't look ALL round you—unless you've got eyes at the back of your head.”
The tone of this passage is best described as
serious and reflective.
scientific and factual.
light and romantic.
imaginative and humorous.Step-by-step explanation:
Answer:
y= 2/3x + 28/3
Step-by-step explanation:
First, write your equation as y=2/3x+b. Plug in your coordinate into the equation, it should look like this: 6=2/3(-5)+b. Multiply 2/3 by -5 to get -10/3. It should look like this: 6= -10/3+b. Add 10/3 to both sides to get your y-intercept of 28/3. Go back to your original equation and plug 28/3 into b. This is your final equation: y= 2/3x + 28/3. Hope this helped!
<h3>Given</h3>
- a cone of height 0.4 m and diameter 0.3 m
- filling at the rate 0.004 m³/s
- fill height of 0.2 m at the time of interest
<h3>Find</h3>
- the rate of change of fill height at the time of interest
<h3>Solution</h3>
The cone is filled to half its depth at the time of interest, so the surface area of the filled portion will be (1/2)² times the surface area of the top of the cone. The filled portion has an area of
... A = (1/4)(π/4)d² = (π/16)(0.3 m)² = 0.09π/16 m²
This area multiplied by the rate of change of fill height (dh/dt) will give the rate of change of volume.
... (0.09π/16 m²)×dh/dt = dV/dt = 0.004 m³/s
Dividing by the coefficient of dh/dt, we get
... dh/dt = 0.004·16/(0.09π) m/s
... dh/dt = 32/(45π) m/s ≈ 0.22635 m/s
_____
You can also write an equation for the filled volume in terms of the filled height, then differentiate and solve for dh/dt. When you do, you find the relation between rates of change of height and area are as described above. We have taken a "shortcut" based on the knowledge gained from solving it this way. (No arithmetic operations are saved. We only avoid the process of taking the derivative.)
Note that the cone dimensions mean the radius is 3/8 of the height.
V = (1/3)πr²h = (1/3)π(3/8·h)²·h = 3π/64·h³
dV/dt = 9π/64·h²·dh/dt
.004 = 9π/64·0.2²·dh/dt . . . substitute the given values
dh/dt = .004·64/(.04·9·π) = 32/(45π)
I’m pretty sure the answer would be A, sorry if i’m incorrect, have a great day :)
