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egoroff_w [7]
3 years ago
13

A rectangular table has an area of

Mathematics
1 answer:
just olya [345]3 years ago
7 0
It would be 3/10 because 4/5 divided by 8/3 is 3/10. Hope that helps
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HELP i’m having trouble with my homework assignments
Aleksandr-060686 [28]

Answer:

Collin: about $401 thousand

Cameron: about $689 thousand

Step-by-step explanation:

A situation in which doubling time is constant is a situation that can be modeled by an exponential function. Here, you're given an exponential function, though you're not told what the variables mean. That function is ...

P(t)=P_0(2^{t/d})

In this context, P0 is the initial salary, t is years, and d is the doubling time in years. The function gives P(t), the salary after t years. In this problem, the value of t we're concerned with is the difference between age 22 and age 65, that is, 43 years.

In Collin's case, we have ...

P0 = 55,000, t = 43, d = 15

so his salary at retirement is ...

P(43) = $55,000(2^(43/15)) ≈ $401,157.89

In Cameron's case, we have ...

P0 = 35,000, t = 43, d = 10

so his salary at retirement is ...

P(43) = $35,000(2^(43/10)) ≈ $689,440.87

___

Sometimes we like to see these equations in a form with "e" as the base of the exponential. That form is ...

P(t)=P_{0}e^{kt}

If we compare this equation to the one above, we find the growth factors to be ...

2^(t/d) = e^(kt)

Factoring out the exponent of t, we find ...

(2^(1/d))^t = (e^k)^t

That is, ...

2^(1/d) = e^k . . . . . match the bases of the exponential terms

(1/d)ln(2) = k . . . . . take the natural log of both sides

So, in Collin's case, the equation for his salary growth is

k = ln(2)/15 ≈ 0.046210

P(t) = 55,000e^(0.046210t)

and in Cameron's case, ...

k = ln(2)/10 ≈ 0.069315

P(t) = 35,000e^(0.069315t)

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X - distance between Jie and Xiaoqing.

\dfrac{x}{24\sqrt{5}}=\sin30^\circ\\\\\\\dfrac{x}{24\sqrt{5}}=\dfrac{1}{2}\qquad\qquad\qquad\text{(cross multiply)}\\\\\\2x=24\sqrt{5}\quad|:2\\\\x=12\sqrt{5}\\\\\boxed{x\approx26.83}
6 0
2 years ago
R0-180(x, y) maps to the same point as 80,180(x, y).<br> True<br> False
mariarad [96]
The anser is false that what i think ):):(:(:(:(:(:
6 0
3 years ago
Miss Sandy is fencing in her rectangular backyard which is 3x^2 feet wide and 4xy + 5x^3 y^2 feet long. Find perimeter of yard H
hjlf

Given:

Width of rectangular backyard = 3x^2 feet

Length of rectangular backyard = 4xy+5x^3y^2 feet

To find:

The perimeter of yard.

Solution:

Formula or perimeter of a rectangle is

Perimeter=2(length +width)

Using this formula, the perimeter of the rectangular backyard is

Perimeter=2(4xy+5x^3y^2+3x^2)

Perimeter=8xy+10x^3y^2+6x^2

Therefore, the perimeter of the rectangular backyard is 8xy+10x^3y^2+6x^2 feet. So, 8xy+10x^3y^2+6x^2 feet fencing is needed.

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