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Marrrta [24]
3 years ago
7

Choose the correct correspondence.

Mathematics
1 answer:
svp [43]3 years ago
6 0

chapati Duniya Lagti Hai Duniya

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Find the three numbers in AP whose sum is 15 and the product is 80​
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Answer:

8,5,2

Step-by-step explanation:

8 , 5, 2 Just use rigorous trial and error

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3 years ago
Simplify and write the answer in exponential form. 3^4 x 3^5 a.) 3^9
givi [52]

Answer:

<h3>(a) 3^9</h3>

Step-by-step explanation:

<h3> IN EXPONNETIAL FORM :</h3>

<h3>– (a^m× a^n) = (a^m+n)</h3>

<h3>3^4 × 3^5 = 3^4+5 = </h3>

<h2>3^9 </h2>

<h3 />
5 0
3 years ago
Heather earns $16 for each hour she works as a lifeguard. Choose the equation that models the situation, where h represents the
lord [1]

Answer:

I'm pretty sure the answer is m = 16h

Hope this helps!

Please mark as brainliest!

5 0
3 years ago
One of the interior angles of a regular polygon is 144. fine the number of sides of the polygon ​
lora16 [44]

Answer:

10

Step-by-step explanation:

In any polygon

exterior angle + interior angle = 180° , thus

exterior angle + 144 = 180 ( subtract 144 from both sides )

exterior angle = 36°

The sum of the exterior angles = 360°

Thus number of sides n is calculated as

n = 360 ÷ 36 = 10

3 0
3 years ago
Read 2 more answers
Could someplease explain the whole problem? For the first part my the answer I got was x= .618, -.618, and <img src="https://tex
algol13

9514 1404 393

Answer:

  a) x = (√5 -1)/2 ≈ 0.618034

  b) 1/x = (√5 +1)/2 ≈ 1.618034

Step-by-step explanation:

<u>Given</u>:

  x/(1 -x) = 1/x

<u>Find</u>:

  Exactly, and as a decimal approximation, ...

  a) x, using the quadratic formula

  b) 1/x

<u>Solution</u>:

a) We can multiply the given equation by x(1 -x) to obtain ...

  x² = 1 -x

  x² +x -1 = 0 . . . . . . add x-1

The coefficients for use in the quadratic formula are a=1, b=1, c=-1. The solution using the quadratic formula is ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-1\pm\sqrt{1^2-4\cdot1\cdot(-1)}}{2\cdot1}=\dfrac{-1\pm\sqrt{5}}{2}

We are only interested in the positive solution, which is ...

  \boxed{x=\dfrac{\sqrt{5}-1}{2}\approx0.618034}

__

b) The quadratic we developed in the first part can be rearranged like this:

  x² +x = 1 . . . . . . add 1 to both sides

  x(x +1) = 1 . . . . . factor out x

  x +1 = 1/x . . . . . .divide by x

Then to find the value of 1/x, we simply need to add 1 to the value of x we have:

  \dfrac{1}{x}=\dfrac{\sqrt{5}-1}{2}+1=\dfrac{\sqrt{5}-1}{2}+\dfrac{2}{2}=\dfrac{\sqrt{5}-1+2}{2}\\\\\boxed{\dfrac{1}{x}=\dfrac{\sqrt{5}+1}{2}\approx1.618034}

5 0
3 years ago
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