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lorasvet [3.4K]
3 years ago
7

When an apple falls from a tree and strikes the ground without bouncing, what

Physics
1 answer:
dalvyx [7]3 years ago
8 0

Answer:

The momentum of the falling apple is transferred to the Earth.

Explanation:

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What do all of the elements in group 13 have in common?
Neko [114]
Each one of the elements in group 13 has three electrons in the outer shell of their nuclear structure
8 0
3 years ago
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How much gravitational potential energy does an object have if it is located 20 m above the point that we define as O height and
raketka [301]

Answer:

Explanation:

PE = mgh where m is the mass in kg, g is the pull of gravity which is 9.8, and h is the height of the object above the point to which it could possibly fall, measured in meters. Plugging in:

PE = 10(9.8)(20) so

PE = 1960 J

This should be rounded to 1 sig fig according to the rules of sig fig and your numbers here, but I imagine you're not following them all that much. It should be 2000 J

8 0
3 years ago
Kevin works for his own gutter and siding company and loves that he gets to climb around and work outside. marsha is an accounta
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I hope both Kevin and Marsha are successful at their jobs,
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7 0
3 years ago
Air expands isentropically from 2.2 MPa and 77°C to 0.4 MPa. Calculate the ratio of the initial to the final speed of sound.
djyliett [7]

Answer:

The ratio of initial to final speed of sound is given as 1.28.

Explanation:

As per the thermodynamic relation of isentropic expansion

\frac{T_2}{T_1}=(\frac{P_2}{P_1})^{\frac{k-1}{k}}

Here

  • P_1 is the pressure at point 1 which is given as 2.2 MPa
  • T_1 is the temperature at point 1 which is given as 77 °C  or 273+77=350K
  • P_2 is the pressure at point 1 which is given as 0.4 MPa
  • T_2 is the temperature at point 2 which is to be calculated
  • k is the ratio of specific heats given as 1.4

Substituting values in the equation

                                      \frac{T_2}{350}=(\frac{0.4}{2.2})^{\frac{1.4-1}{1.4}}\\\frac{T_2}{350}=(0.18)^{0.2857}\\T_2=(0.18)^{0.2857} \times 350 \\T_2=0.61266 \times 350\\T_2=214.43 K

As speed of sound c is given as

c=\sqrt{kRT}

for initial to final values it is given as

\frac{c_i}{c_f}=\frac{\sqrt{k_1R_1T_1}}{\sqrt{k_2R_2T_2}}

As values of k and R is constant so the ratio is given as

\frac{c_i}{c_f}=\sqrt{\frac{T_1}{T_2}}

Substituting values give

\frac{c_i}{c_f}=\sqrt{\frac{350}{214.43}}\\\frac{c_i}{c_f}=\sqrt{1.63}}\\\frac{c_i}{c_f}=1.277  \approx 1.28

So the ratio of initial to final speed of sound is 1.28.

5 0
3 years ago
A spaceship, at rest in some inertial frame in space, suddenly needs to accelerate. The ship forcibly expels 103 kg of fuel from
Cerrena [4.2K]

Answer:

V_s = 1.8*10^5m/s

Explanation:

There is no external force applied, therefore there is a moment's preservation throughout the trajectory.

<em>Initial momentum  = Final momentum. </em>

The total mass is equal to

m_T= m_1 +m_2

Where,

m_1 = mass of ship

m_2 = mass of fuell expeled.

As the moment is conserved we have,

0=V_fm_2+V_sm_1

Where,

V_f = Velocity of fuel

V_s =Velocity of Space Ship

Solving and re-arrange to V_swe have,

V_s = \frac{V_f m_2 }{m_1}

V_s = \frac{3/5c}{10^6}

V_s = 3.5*10^{-3}c

Where c is the speed of light.

Therefore the ship be moving with speed

V_s = \frac{3}{5}*10^{-3}*3*10^8m/s

V_s = 1.8*10^5m/s

5 0
3 years ago
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