Question

A 13,500 kg railroad freight car travels on a level track at a speed of 4.5 m/s. It collides and couples with a 25,000 kg second car, initially at rest and with brakes released. What is the speed of the two cars after collision?

Answer 1

Answer:

V = 1.578m/s

Explanation:

(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V

(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V

60750 + 0 = (38500)V

60750 = 38500V

V = 60750/38500

V = 1.578m/s