A spaceship, at rest in some inertial frame in space, suddenly needs to accelerate. The ship forcibly expels 103 kg of fuel from
1 answer:
Answer:
Explanation:
There is no external force applied, therefore there is a moment's preservation throughout the trajectory.
<em>Initial momentum = Final momentum. </em>
The total mass is equal to
Where,
mass of ship
mass of fuell expeled.
As the moment is conserved we have,
Where,
Velocity of fuel
Velocity of Space Ship
Solving and re-arrange to we have,
Where c is the speed of light.
Therefore the ship be moving with speed
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Answer:
14112 J
Explanation:
When the 72 Kg mass explodes into two, one mass is twice the other so 72/3=24 Kg
M1= 24 kg, M2= 72-24=48 kg
From law of conservation of linear momentum, the sum of initial and final momentum are equal. p=mv where p is momentum, m is mass and v is velocity. Fir this case, since the less massive piece stops, its final velocity is zero.
72*28=48v2
V2=72*28/48=42 m/s
Difference between initial and final kinetic energy will be
Therefore, from observers reference, kinetic energy of 14112 J is added
First body:
Second body:
From description of the task we have:
Second body:
From description of the task we have: