Determinar la fuerza que recibe un cuerpo de 145 kg, la cual le produce una aceleracion cuya magnitud es de 3.5 m/s2
1 answer:
Answer:
<em>El cuerpo recibe una fuerza neta de 507.5 N</em>
Explanation:
<u>Segunda Ley de Newton</u>
La fuerza neta F aplicada a un cuerpo de masa m que produce una aceleración a se calcula con la fórmula:
F = ma
Sabemos que un cuerpo de masa m=145 kg al que se le aplica una fuerza neta F, adquiere una aceleración .
Calculamos la fuerza neta:
F = 507.5 N
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Answer:
(i) , (ii)
, (iii)
Explanation:
(i) and
represent the points where particle has a velocity of zero and spring reach maximum deformation, Given the absence of non-conservative force and by the Principle of Energy Conservation, the position where particle is at maximum speed is average of both extreme positions:
(ii) Maximum accelerations is reached at and
.
(iii) Greatest net forces exerted on the particle are reached at and
.
Answer:
(a) 0.942 m
(b) 18.84 m/s
(c) 2366.3 m/s²
(d) 0.05 s
Explanation:
(a) In one revolution, it travels through one circumference, 2πr = 2 × 3.14 × 0.15 m = 0.942 m.
(b) Its frequency, f, is 1200 rev/min = rev/s = 20 rev/s.
Its angular frequency, ω = 2πf = 2π × 20 = 40π
The speed is given by
v = ωr = 40π × 0.15 = 6π = 18.84 m/s
(c) Its acceleration is given by, a = ω²r = (40π)² × 0.15 = 2366.3 m/s²
(d) The period is the inverse of the frequency because it is the time taken to complete one revolution.
T = 1/20 = 0.05 s