Hrs

The roots of a quadratic equation depend on the values of the coefficients.<br><br> True<br> False

oksano4ka [1.4K]

Answer:

True

Step-by-step explanation:

The nature of roots of a quadratic equation are determined by

${b}^{2} - 4ac$

where a, b, and c are the coefficients of the quadratic equation

$a {x}^{2} + bx + c = 0$

Therefore it is true that, the roots of a quadratic equation depend on the values of the coefficients.

6 0

3 years ago

What is the domain of the function in this table

never [62]

Option A:

{3, 4, 5, 6}

Solution:

In the given table X column have 3, 4, 5, 6 and Y column have 4, 4, 2, 5.

The domain is the set of all values for which the function is defined.

The domain of the function is set of all X values.

Option A: {3, 4, 5, 6}

Set of all X values {3, 4, 5, 6}.

It is correct.

Option B: (3, 4), (4, 4), (5, 2), (6, 5)

Here, the given values are ordered pairs of domain and co-domain.

It is not correct.

Option C: (3, 4)

Here, (3, 4) is a ordered pair of domain and co-domain.

It is not correct.

Option D: {2, 4, 5}

Here, {2, 4, 5} are values of co-domain.

It is not correct.

Hence {3, 4, 5, 6} is the domain of the function.

3 0

3 years ago

State the 3 primary Trigonometrie Formulas and draw a well labelled triangle to help illustre, cely

uysha [10]

Answer:

I think this is what you want:

Step-by-step explanation:

5 0

3 years ago

2. Solve the following system. Show all your work. -3x + 2y + z = -6 x + 3y + 2z = 5 4x + 4y + 3z = 13 Is there a step I'm skipp

mr Goodwill [35]

-3x + 2y + z = -6

(3)x + 3y + 2z = 5(3) We want to get rid of any variable within 2 equations. The easiest one would be by multiplying both sides of eq#2 by 3 and add it to eq#1.

-3x+2y+z=-6

3x+9y+6z=15

Add them together to get 11y+7z=9

(-4)x+3y+2z=5(-4) Now,multiply the original eq#2 by -4 to cancel out x in the last equation

-4x-12y-8z=-20

4x + 4y + 3z = 13

add them together to get -8y-5z=-7

Now multiply the eq 11y+7z=9 by 5 and the equation -8y-5z=-7 by 7 to cancel out the z variable when we add them together.

Once we multiply them, we get

-56y-35z=-49

55y+35z=45

add them together to get -y=-4 and we know y=4

substitute y into any equation here that has y and any other 1 variable like -8y-5z=-7 and get z=-5

Finally, we know y=4 and z=-5, we can substitue that into any of the original eqs like -3x + 2y + z = -6 and we get x=-3

To check, just substitute these values into any of the equations above

4 0

3 years ago

What is the equation

Vesna [10]

Answer:

$y = \sin( \frac{2\pi}{3} x)$

Step-by-step explanation:

The equation of a sine function is y = a sin(bx), where a = amplitude (aka height) and b equals period (aka time). I'm assuming there isn't any information other than the graph shown, so let's assume that our amplitude is 1 and our period is 2pi/3. Plugging these values into the equation, we get:

$y = (1) \sin(( \frac{2\pi}{3})x ) = \sin(\frac{2{\pi} }{3}x )$

3 0

2 years ago