Answer:
1.) 2x-y=-7 --> y=2x + 7
2.) 5x+3y=12 --> y= -5/3x + 4
3.) x-y=1 --> y= x- 1
4.) x-3y=-15 --> y=1/3x + 5
5.) 8x-10y=20 --> y=4/5x - 2
6.) 14x+6y=36 --> y=-7/3x+6
Step-by-step explanation:
Hope this helped.
Answer:
d = 4
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₁ = - 2 and a₈ = 26 , then
- 2 + 7d = 26 ( add 2 to both sides (
7d = 28 ( divide both sides by 7 )
d = 4
Answer:
The expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].
Step-by-step explanation:
The formula to compute the future value is:
![FV=PV[1+\frac{r}{100}]^{n}](https://tex.z-dn.net/?f=FV%3DPV%5B1%2B%5Cfrac%7Br%7D%7B100%7D%5D%5E%7Bn%7D)
PV = Present value
r = interest rate
n = number of periods.
It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.
The expression to compute the amount in the investment account after 14 years is,
![FV=5000[1+\frac{10}{100}]^{14}+3000[1+\frac{10}{100}]^{14-6}\\FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}](https://tex.z-dn.net/?f=FV%3D5000%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%5E%7B14%7D%2B3000%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%5E%7B14-6%7D%5C%5CFV%3D5000%5B1%2B0.10%5D%5E%7B14%7D%2B3000%5B1%2B0.10%5D%5E%7B8%7D)
The future value is:
![FV=5000[1+0.10]^{14}+3000[1+0.10]^{8}\\=18987.50+6430.77\\=25418.27](https://tex.z-dn.net/?f=FV%3D5000%5B1%2B0.10%5D%5E%7B14%7D%2B3000%5B1%2B0.10%5D%5E%7B8%7D%5C%5C%3D18987.50%2B6430.77%5C%5C%3D25418.27)
Thus, the expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].
150 / 200 = 0.75
0.75 = 75%
150 of anything is 75% of 200 of the same thing.
The answer is 10. I hope that this helped ☻